Is there a concise way to iterate over a stream with indices in Java 8?

Question

Is there a concise way to iterate over a stream whilst having access to the index in the stream?

String[] names = {\"Sam\",\"Pamela\", \"Dave\", \"Pascal\",          


        

Answer 1

You can use IntStream.iterate() to get the index:

String[] names = {"Sam","Pamela", "Dave", "Pascal", "Erik"};
List<String> nameList = IntStream.iterate(0, i -> i < names.length, i -> i + 1)
        .filter(i -> names[i].length() <= i)
        .mapToObj(i -> names[i])
        .collect(Collectors.toList());

This only works for Java 9 upwards in Java 8 you can use this:

String[] names = {"Sam","Pamela", "Dave", "Pascal", "Erik"};
List<String> nameList = IntStream.iterate(0, i -> i + 1)
        .limit(names.length)
        .filter(i -> names[i].length() <= i)
        .mapToObj(i -> names[i])
        .collect(Collectors.toList());

Answer 2

Here is code by AbacusUtil

Stream.of(names).indexed()
      .filter(e -> e.value().length() <= e.index())
      .map(Indexed::value).toList();

Disclosure： I'm the developer of AbacusUtil.

Answer 3

Since guava 21, you can use

Streams.mapWithIndex()

Example (from official doc):

Streams.mapWithIndex(
    Stream.of("a", "b", "c"),
    (str, index) -> str + ":" + index)
) // will return Stream.of("a:0", "b:1", "c:2")

Answer 4

There isn't a way to iterate over a Stream whilst having access to the index because a Stream is unlike any Collection. A Stream is merely a pipeline for carrying data from one place to another, as stated in the documentation:

No storage. A stream is not a data structure that stores elements; instead, they carry values from a source (which could be a data structure, a generator, an IO channel, etc) through a pipeline of computational operations.

Of course, as you appear to be hinting at in your question, you could always convert your Stream<V> to a Collection<V>, such as a List<V>, in which you will have access to the indexes.