How do I launch a program from command line without opening a new cmd window?

Question

I\'m trying to programmatically execute an external file from cmd using this command:

START \"filepath\"

Where \"filepat

Answer 1

I think if you closed a program

taskkill /f /im "winamp.exe" 
//....(winamp.exe is example)...

end, so if you want to start a program that you can use

start "" /normal winamp.exe 

(/norma,/max/min are that process value cpu)

ALSO

start "filepath"

if you want command line without openning an new window you write that

start /b "filepath"

/B is Start application without creating a new window. The application has ^C handling ignored. Unless the application enables ^C processing, ^Break is the only way to interrupt the application.

Answer 2

If you're doing it via CMD as you say, then you can just enter the command like so:

path\to\your.exe 

which will open it within the same window. For example in C++:

system("path\\to\\your.exe"); // Double backslash for escaping

will open your.exe in the current CMD window. Likewise to start with a new window, just go for:

system("start path\\to\\your.exe");

If you go for the first option, you would have to clear your screen unless you wanted to have the command to open your.exe on the screen still.

Answer 3

Just remove the double quote, this works in Windows 7:

start C:\ProgramFiles\folderName\app.exe

If you want to maximize the window, try this:

start /MAX C:\ProgramFiles\folderName\app.exe

Your command START "filepath" will start a command prompt and change the command prompt title to filepath.

Try to run start /? in windows command prompt and you will get more info.