Find all numbers in the String [closed]

Answer 1

try this code

String s = "qwerty1qwerty2";
for(int i=0;i<s.length();i++)
{
   if(Character.isDigit(s.charAt(i)))
   System.out.print(s.charAt(i)+"  ");
}

Answer 2

import java.util.regex.Matcher;
import java.util.regex.Pattern;

...

Pattern pattern = Pattern.compile("[0-9]+"); 
Matcher matcher = pattern.matcher("test1string1337thingie");

// Find all matches
while (matcher.find()) { 
  // Get the matching string  
  String match = matcher.group();
}

Is one regexp solution.

Answer 3

Use RepalceAll

String str = "qwerty1qwerty2";      
str = str.replaceAll("[^0-9]+", " ");
System.out.println(Arrays.asList(str.trim().split(" ")));

Output:

[1, 2]

[EDIT]

If you want to include - a.e minus, add -?:

String str = "qwerty-1qwerty-2 455 f0gfg 4";      
str = str.replaceAll("[^-?0-9]+", " "); 
System.out.println(Arrays.asList(str.trim().split(" ")));

Output:

[-1, -2, 455, 0, 4]

---

Description

[^-?0-9]+

• + Between one and unlimited times, as many times as possible, giving back as needed
• -? One of the characters “-?”
• 0-9 A character in the range between “0” and “9”