why referencing non-existent property of an object in javascript doesn't return a reference error?

Question

If I try to reference a non-existent variable, I get ReferenceError in JavaScript. Why referencing a non-existent object property returns \'undefined\'? Here is some code, p

Answer 1

That's just how the language works. Its object-based approach is very flexible, and you can dynamically add, update, and remove properties from objects at runtime. Accessing one that is currently not existing should yield undefined instead of raising an exception. This, for example, allows checking for existence and type in a single expression:

if (prop in obj && typeof obj[prop] == "function") obj[prop]();
// can be written shorter:
if (typeof obj[prop] == "function") obj[prop]();

You can get the value without using it. Using undefined then will throw in most circumstances.

In contrast, variables are declared statically in their scope. Accessing an undeclared variable is always an error, which legitimates throwing ReferenceErrors.