Currently I do the following:
// float *c_array = new float[1024];
void Foo::foo(float *c_array, size_t c_array_size) {
//std::vector cpp_arr
The only way to do it would be to create a custom allocator.
Write an allocator class that you can initialise with your array.
Instantiate the vector with the allocator as an argument.
Currently, the std::vector
interface does not possess the capacity to move from or swap with anything except another std::vector
.
The current std::vector
doesn't provide any capability or interface to take ownership of previously allocated storage. Presumably it would be too easy to pass a stack address in by accident, allowing more problems than it solved.
If you want to avoid copying into a vector, you'll either need to use vectors through your entire call chain, or do it the C way with float[]
the entire time. You can't mix them. You can guaranteed that &vec[0]
will be equivalent to the C-array though, fully contiguous, so using vector in the whole program may be feasible.
Unlikely it's possible - it's quite dangerous, because std::vector doesn't know how the memory was allocated and how it should be freed.
If it's possible, you may replace original allocation with creation of std::vector of correct size. It uses contiguous memory area, so it can replace manually allocated buffer.