In your particular example, none because the compiler internally uses StringBuilder
s to do String concatenation. If the concatenation occurred in a loop, however, the compiler could create several StringBuilder
and String
objects. For example:
String s= "" ;
for(int i= 0 ; i < 10 ; i++ )
s+= "a" ;
Each time line 3 above is executed, a new StringBuilder
object is created, the contents of s
appended, "a" appended, and then the StringBuilder
is converted into a String to be assigned back to s
. A total of 10 StringBuilder
s and 10 String
s.
Conversely, in
StringBuilder sb= new StringBuilder() ;
for(int i= 0 ; i < 10 ; i++ )
sb.append( "a" );
String s= sb.toString() ;
Only 1 StringBuilder
and 1 String
are created.
The main reason for this is that the compiler could not be smart enough to understand that the first loop is equivalent to the second and generate more efficient (byte) code. In more complex cases, it's impossible even for the smartest compiler to know. If you absolutely need this optimization, you have to introduce it manually by using StringBuilder
s explicitly.