How do I redirect stdout to a file when using subprocess.call in python?

Question

I\'m calling a python script (B) from another python script (A).

Using subprocess.call, how do I redirect the stdout of B to a file that specify?

I\'m using

Answer 1

Pass a file as the stdout parameter to subprocess.call:

with open('out-file.txt', 'w') as f:
    subprocess.call(['program'], stdout=f)

Answer 2

Alternate approach

import subprocess
p=subprocess.Popen('lsblk -l|tee a.txt',stdout=subprocess.PIPE,shell=True)
(output,err)=p.communicate()
p_status=p.wait()
print output

Above code will write output of command to file a.txt