How to convert strings into integers in Python?

Question

I have a tuple of tuples from a MySQL query like this:

T1 = ((\'13\', \'17\', \'18\', \'21\', \'32\'),
      (\'07\', \'11\', \'13\', \'14\', \'28\'),
               


        

Answer 1

Try this.

x = "1"

x is a string because it has quotes around it, but it has a number in it.

x = int(x)

Since x has the number 1 in it, I can turn it in to a integer.

To see if a string is a number, you can do this.

def is_number(var):
    try:
        if var == int(var):
            return True
    except Exception:
        return False

x = "1"

y = "test"

x_test = is_number(x)

print(x_test)

It should print to IDLE True because x is a number.

y_test = is_number(y)

print(y_test)

It should print to IDLE False because y in not a number.

Answer 2

In Python 3.5.1 things like these work:

c = input('Enter number:')
print (int(float(c)))
print (round(float(c)))

and

Enter number:  4.7
4
5

George.

Answer 3

See this function

def parse_int(s):
    try:
        res = int(eval(str(s)))
        if type(res) == int:
            return res
    except:
        return

Then

val = parse_int('10')  # Return 10
val = parse_int('0')  # Return 0
val = parse_int('10.5')  # Return 10
val = parse_int('0.0')  # Return 0
val = parse_int('Ten')  # Return None

You can also check

if val == None:  # True if input value can not be converted
    pass  # Note: Don't use 'if not val:'

Answer 4

Instead of putting int( ), put float( ) which will let you use decimals along with integers.

Answer 5

Using list comprehensions:

t2 = [map(int, list(l)) for l in t1]

Answer 6

I would rather prefer using only comprehension lists:

[[int(y) for y in x] for x in T1]