Split Java String by New Line

Question

I\'m trying to split text in a JTextArea using a regex to split the String by \\n However, this does not work and I also tried by \\r\\n|\\r|

Answer 1

A new method lines has been introduced to String class in java-11, which returns Stream<String>

Returns a stream of substrings extracted from this string partitioned by line terminators.

Line terminators recognized are line feed "\n" (U+000A), carriage return "\r" (U+000D) and a carriage return followed immediately by a line feed "\r\n" (U+000D U+000A).

Here are a few examples:

jshell> "lorem \n ipusm \n sit".lines().forEach(System.out::println)
lorem
 ipusm
 sit

jshell> "lorem \n ipusm \r  sit".lines().forEach(System.out::println)
lorem
 ipusm
  sit

jshell> "lorem \n ipusm \r\n  sit".lines().forEach(System.out::println)
lorem
 ipusm
  sit

String#lines()

Answer 2

If, for some reason, you don't want to use String.split (for example, because of regular expressions) and you want to use functional programming on Java 8 or newer:

List<String> lines = new BufferedReader(new StringReader(string))
        .lines()
        .collect(Collectors.toList());

Answer 3

There are three different conventions (it could be said that those are de facto standards) to set and display a line break:

• carriage return + line feed
• line feed
• carriage return

In some text editors, it is possible to exchange one for the other:

The simplest thing is to normalize to line feedand then split.

final String[] lines = contents.replace("\r\n", "\n")
                               .replace("\r", "\n")
                               .split("\n", -1);

Answer 4

This should cover you:

String lines[] = string.split("\\r?\\n");

There's only really two newlines (UNIX and Windows) that you need to worry about.

Answer 5

String.split(System.getProperty("line.separator"));

This should be system independent

Answer 6

The above code doesnt actually do anything visible - it just calcualtes then dumps the calculation. Is it the code you used, or just an example for this question?

try doing textAreaDoc.insertString(int, String, AttributeSet) at the end?