Dynamically add properties to a existing object

Question

I create the person object like this.

 Person person=new Person(\"Sam\",\"Lewis\") 

It has properties like this.

person.Dob         


        

Answer 1

If you have a class with an object property, or if your property actually casts to an object, you can reshape the object by reassigning its properties, as in:

  MyClass varClass = new MyClass();
  varClass.propObjectProperty = new { Id = 1, Description = "test" };

  //if you need to treat the class as an object
  var varObjectProperty = ((dynamic)varClass).propObjectProperty;
  ((dynamic)varClass).propObjectProperty = new { Id = varObjectProperty.Id, Description = varObjectProperty.Description, NewDynamicProperty = "new dynamic property description" };

  //if your property is an object, instead
  var varObjectProperty = varClass.propObjectProperty;
  varClass.propObjectProperty = new { Id = ((dynamic)varObjectProperty).Id, Description = ((dynamic)varObjectProperty).Description, NewDynamicProperty = "new dynamic property description" };

With this approach, you basically rewrite the object property adding or removing properties as if you were first creating the object with the

new { ... }

syntax.

In your particular case, you're probably better off creating an actual object to which you assign properties like "dob" and "address" as if it were a person, and at the end of the process, transfer the properties to the actual "Person" object.

Answer 2

If you can't use the dynamic type with ExpandoObject, then you could use a 'Property Bag' mechanism, where, using a dictionary (or some other key / value collection type) you store string key's that name the properties and values of the required type.

See here for an example implementation.

Answer 3

It's not possible with a "normal" object, but you can do it with an ExpandoObject and the dynamic keyword:

dynamic person = new ExpandoObject();
person.FirstName = "Sam";
person.LastName = "Lewis";
person.Age = 42;
person.Foo = "Bar";
...

If you try to assign a property that doesn't exist, it is added to the object. If you try to read a property that doesn't exist, it will raise an exception. So it's roughly the same behavior as a dictionary (and ExpandoObject actually implements IDictionary<string, object>)

Answer 4

If you only need the dynamic properties for JSON serialization/deserialization, eg if your API accepts a JSON object with different fields depending on context, then you can use the JsonExtensionData attribute available in Newtonsoft.Json or System.Text.Json.

Example:

public class Pet
{
    public string Name { get; set; }
    public string Type { get; set; }

    [JsonExtensionData]
    public IDictionary<string, object> AdditionalData { get; set; }
}

Then you can deserialize JSON:

public class Program
{
    public static void Main()
    {
        var bingo = JsonConvert.DeserializeObject<Pet>("{\"Name\": \"Bingo\", \"Type\": \"Dog\", \"Legs\": 4 }");
        Console.WriteLine(bingo.AdditionalData["Legs"]);        // 4

        var tweety = JsonConvert.DeserializeObject<Pet>("{\"Name\": \"Tweety Pie\", \"Type\": \"Bird\", \"CanFly\": true }");
        Console.WriteLine(tweety.AdditionalData["CanFly"]);     // True

        tweety.AdditionalData["Color"] = "#ffff00";

        Console.WriteLine(JsonConvert.SerializeObject(tweety)); // {"Name":"Tweety Pie","Type":"Bird","CanFly":true,"Color":"#ffff00"}
    }
}

Answer 5

Consider using the decorator pattern http://en.wikipedia.org/wiki/Decorator_pattern

You can change the decorator at runtime with one that has different properties when an event occurs.

Answer 6

Take a look at the Clay library:

http://clay.codeplex.com/

It provides something similar to the ExpandoObject but with a bunch of extra features. Here is blog post explaining how to use it:

http://weblogs.asp.net/bleroy/archive/2010/08/18/clay-malleable-c-dynamic-objects-part-2.aspx

(be sure to read the IPerson interface example)