Isn\'t it possible to set the type of a parameter to an Enum? Like this:
private getRandomElementOfEnum(e : enum):string{
var length:number = Object.
I agree with @Tarh. Enums in TypeScript are just Javascript objects without a common interface or prototype (and if they are const enum
, then they are not even objects), so you cannot restrict types to "any enum".
The closest I could get is something like the following:
enum E1 {
A, B, C
}
enum E2 {
X, Y, Z
}
// make up your own interface to match TypeScript enums
// as closely as possible (not perfect, though)
interface Enum {
[id: number]: string
}
function getRandomElementOfEnum(e: Enum): string {
let length = Object.keys(e).length / 2;
return e[Math.floor((Math.random() * length))];
}
This works for all enums (without custom initializers), but it would also accept other arrays as input (and then fail because the method body relies on the very specific key structure that TypeScript enums have).
So unless you have a real need for such a "generic" function, make typesafe functions for the individual enum types (or a union type like E1|E2|E3
) that you actually need.
And if you do have this need (and this might very well be an X-Y-problem that can be solved in a better, completely different way given more context), use any
, because you have left typesafe territory anyway.
Summing up the previous answers with some new syntax - a generic typesafe function, which works with numeric enums as well as string enums:
function getRandomElementOfEnum<T extends {[key: number]: string | number}>(e: T): T[keyof T] {
const keys = Object.keys(e);
const randomKeyIndex = Math.floor(Math.random() * keys.length);
const randomKey = keys[randomKeyIndex];
// Numeric enums members also get a reverse mapping from enum values to enum names.
// So, if a key is a number, actually it's a value of a numeric enum.
// see https://www.typescriptlang.org/docs/handbook/enums.html#reverse-mappings
const randomKeyNumber = Number(randomKey);
return isNaN(randomKeyNumber)
? e[randomKey as keyof T]
: randomKeyNumber as unknown as T[keyof T];
}
May be this trick will fit:
enum AbstractEnum { // put somewhere in hidden scope
}
private getRandomElementOfEnum(e: typeof AbstractEnum) {
...
}
Tested on TypeScript 3.9.7
type EnumTypeString<TEnum extends string> =
{ [key in string]: TEnum | string; }
type EnumTypeNumber<TEnum extends number> =
{ [key in string]: TEnum | number; }
| { [key in number]: string; }
type EnumType<TEnum extends string | number> =
(TEnum extends string ? EnumTypeString<TEnum> : never)
| (TEnum extends number ? EnumTypeNumber<TEnum> : never)
type EnumOf<TEnumType> = TEnumType extends EnumType<infer U>
? U
: never
function forEachEnum<TEnum extends string | number>(
enumType: EnumType<TEnum>,
callback: (value: TEnum, key: string) => boolean|void,
) {
for (let key in enumType) {
if (Object.prototype.hasOwnProperty.call(enumType, key) && isNaN(Number(key))) {
const value = enumType[key] as any
if (callback(value, key)) {
return
}
}
}
}
EnumOf:
function forEachEnum2<TEnumType>(
enumType: TEnumType,
callback: (value: EnumOf<TEnumType>, key: string) => boolean|void,
) {
for (let key in enumType) {
if (Object.prototype.hasOwnProperty.call(enumType, key) && isNaN(Number(key))) {
const value = enumType[key] as any
if (callback(value, key)) {
return
}
}
}
}
enum EnumAsString {
Value1 = 'value 1',
Value2 = 'value 2',
}
enum EnumAsNumber {
Value1 = 1,
Value2 = 2,
}
// Error
let sn: EnumType<string> = EnumAsNumber
// Correct
let ns: EnumType<number> = EnumAsString // I have not found a solution for the error here
let nn: EnumType<number> = EnumAsNumber
let Nn: EnumType<EnumAsNumber> = EnumAsNumber
let ss: EnumType<string> = EnumAsString
let Ss: EnumType<EnumAsString> = EnumAsString
forEachEnum(EnumAsString, value => {
let e: EnumAsString = value
let s: string = value
let n: number = value // Error
})
forEachEnum(EnumAsNumber, value => {
let e: EnumAsNumber = value
let s: string = value // Error
let n: number = value
})
forEachEnum2(EnumAsString, value => {
let e: EnumAsString = value
let s: string = value
let n: number = value // Error
})
forEachEnum2(EnumAsNumber, value => {
let e: EnumAsNumber = value
let s: string = value // Error
let n: number = value
})
You can do better than any
:
enum E1 {
A, B, C
}
enum E2 {
X, Y, Z
}
function getRandomElementOfEnum(e: { [s: number]: string }): number {
/* insert working implementation here */
return undefined;
}
// OK
var x: E1 = getRandomElementOfEnum(E1);
// Error
var y: E2 = getRandomElementOfEnum(window);
// Error
var z: string = getRandomElementOfEnum(E2);
Here is an example that allows passing an enum with a typechecked value of that enum using a generic. It's really a response to a slightly different question here that was marked as a duplicate: Typescript how to pass enum as Parameter
enum Color {
blue,
};
enum Car {
cadillac,
};
enum Shape {
square,
}
type SupportedEnums = typeof Color | typeof Car;
type InvertTypeOf<T> = T extends typeof Color ? Color :
T extends typeof Car ? Car : never;
function getText<T extends SupportedEnums>(enumValue: InvertTypeOf<T>, typeEnum: T) string | undefined {
if (typeEnum[enumValue]) {
return `${enumValue}(${typeEnum[enumValue]})`;
}
}
console.log(getText(Car.cadillac, Car)); // 0(cadillac)
console.log(getText(0, Color)); // 0(red)
console.log(getText(4, Color)); // undefined
// @ts-expect-error Color is not Car
console.log(getText(Color.blue, Car));
// @ts-expect-error Car is not a Color
console.log(getText(Car.toyota, Color));
// @ts-expect-error Shape is not in SupportedEnums
console.log(getText(5, Shape));
// @ts-expect-error Shape is not in SupportedEnums
console.log(getText(Shape.square, Shape));