Java Executors: how can I stop submitted tasks?

Question

I have submitted a task using executors and I need it to stop after some time (e.g. 5 minutes). I have tried doing like this:

   for (Future fut : e         


        

Answer 1

The most common case for ConcurrentModificationException is when the vector is being modified at the same time as it is being iterated. Often this will be done in a single thread. You need to hold a lock on the Vector for the whole iteration (and careful not to deadlock).

Answer 2

Just because you call cancel() on Future doesn't mean that the task will stop automatically. You have to do some work within the task to make sure that it will stop:

• Use cancel(true) so that an interrupt is sent to the task.
• Handle InterruptedException. If a function in your task throws an InterruptedException, make sure you exit gracefully as soon as possible upon catching the exception.
• Periodically check Thread.currentThread().isInterrupted() if the task does continuous computation.

For example:

class LongTask implements Callable<Double> {
    public Double call() {
        
         // Sleep for a while; handle InterruptedException appropriately
         try {
             Thread.sleep(10000);
         } catch (InterruptedException ex) {
             System.out.println("Exiting gracefully!");
             return null;
         }


         // Compute for a while; check Thread.isInterrupted() periodically
         double sum = 0.0;
         for (long i = 0; i < 10000000; i++) {
             sum += 10.0
             if (Thread.currentThread().isInterrupted()) {
                 System.out.println("Exiting gracefully");
                 return null;
             }
         }

         return sum;
    } 
}

Also, as other posts have mentioned: ConcurrentModificationException can be thrown even if using the thread-safe Vector class, because iterators you obtain from Vector are not thread-safe, and thus need to be synchronized. The enhanced for-loop uses iterators, so watch out:

final Vector<Double> vector = new Vector<Double>();
vector.add(1.0);
vector.add(2.0);

// Not thread safe!  If another thread modifies "vector" during the loop, then
// a ConcurrentModificationException will be thrown.
for (Double num : vector) {
    System.out.println(num);
}

// You can try this as a quick fix, but it might not be what you want:
synchronized (vector) {    // "vector" must be final
    for (Double num : vector) {
        System.out.println(num);
    }
}

Answer 3

Put the fut.cancel(true); in the finally block

Answer 4

fut.get() is a blocking call, even after the timeout, you will block until the task is done. If you want to stop as close to the 5 minute mark as possible, you do need to check the interrupt flag, I just recommend you do so using the Thread.isInterrupted() method which preserves the interrupt state. If you want to just stop immediately and don't need to clean any state, then throw an exception which will be caught by the Future and indicated to you as an ExecutionException.

fut.cancel(true) does not do anything as the invokeAll() method has already done this for you.

Unless you use the "tasks" Collection somewhere else, you probably don't need to call clear() on it. This isn't going to be the source of your problem since the invokeAll() method is done with the List by the time you call clear(). But, if you need to start forming a list of new tasks to execute, I suggest you form a new List of tasks, not use an old List of new Tasks.

Unfortunately, I do not have an answer for your problem. I do not see enough information here to diagnose it. Nothing in the code snippet you provided indicates an improper (only unnecessary) use of library classes/methods. Perhaps if you included a full stack trace, instead of the one line error.

Answer 5

The ConcurrentModificationException is coming from your call to tasks.clear() while your Exceutors is iterating over your tasks Vector. What you can try to do is call shutdownNow() on your ExecutorService