Ansible shell module returns error when grep results are empty

前端 未结 2 528
遇见更好的自我
遇见更好的自我 2020-12-01 12:33

I am using Ansible\'s shell module to find a particular string and store it in a variable. But if grep did not find anything I am getting an error.

Example:

相关标签:
2条回答
  • 2020-12-01 12:33

    grep by design returns code 1 if the given string was not found. Ansible by design stops execution if the return code is different from 0. Your system is working properly.

    To prevent Ansible from stopping playbook execution on this error, you can:

    • add ignore_errors: yes parameter to the task

    • use failed_when: parameter with a proper condition

    Because grep returns error code 2 for exceptions, the second method seems more appropriate, so:

    - name: Get the http_status
      shell: grep "http_status=" /var/httpd.txt
      register: cmdln
      failed_when: "cmdln.rc == 2"
      check_mode: no
    

    You might also consider adding changed_when: false so that the task won't be reported as "changed" every single time.

    All options are described in the Error Handling In Playbooks document.

    0 讨论(0)
  • 2020-12-01 12:43

    Like you observed, ansible will stop execution if the grep exit code is not zero. You can ignore it with ignore_errors.

    Another trick is to pipe the grep output to cat. So cat exit code will always be zero since its stdin is grep's stdout. It works if there is a match and also when there is no match. Try it.

    - name: Get the http_status
      shell: grep "http_status=" /var/httpd.txt | cat
      register: cmdln
      check_mode: no
    
    0 讨论(0)
提交回复
热议问题