In PHP, is there an easy way to get the first and last date of a month?

Question

I need to get the first and last day of a month in the format YYYY-MM-DD given only the month and year. Is there a good, easy way to do this?

Answer 1

Just to verify that I didn't miss any loose ends:

$startDay = 1;

if (date("m") == 1) {
    $startMonth = 12;
    $startYear = date("Y") - 1;

    $endMonth = 12;
    $endYear = date("Y") - 1;
}
else {
    $startMonth = date("m") - 1;
    $startYear = date("Y");

    $endMonth = date("m") - 1;
    $endYear = date("Y");
}

$endDay = date("d") - 1;

$startDate = date('Y-m-d', mktime(0, 0, 0, $startMonth , $startDay, $startYear));
$endDate = date('Y-m-d', mktime(0, 0, 0, $endMonth, $endDay, $endYear));

Answer 2

<?php
echo "Month Start - " . $monthStart = date("Y-m-1") . "<br/>";
$num = cal_days_in_month(CAL_GREGORIAN, date("m"), date("Y"));
echo "Monthe End - " . $monthEnd = date("Y-m-".$num);
?>

Answer 3

OK, first is dead easy.

date ('Y-m-d', mktime(0,0,0,MM,01,YYYY));

Last is a little trickier, but not much.

date ('Y-m-d', mktime(0,0,0,MM + 1,-1,YYYY));

If I remember my PHP date stuff correctly...

**edit - Gah! Beaten to it about a million times...

Edit by Pat:

Last day should have been

date ('Y-m-d', mktime(0,0,0,$MM + 1,0,$YYYY)); // Day zero instead of -1

Answer 4

First day is always YYYY-MM-01, isn't it? Example: date("Y-M-d", mktime(0, 0, 0, 8, 1, 2008))

Last day is the previous day of the next month's first day:

$date = new DateTime("2008-09-01");
$date->modify("-1 day");
echo $date->format("Y-m-d");

Answer 5

try this to get the number of days in the month:

$numdays = date('t', mktime(0, 0, 0, $m, 1, $Y));