In PHP, is there an easy way to get the first and last date of a month?

Question

I need to get the first and last day of a month in the format YYYY-MM-DD given only the month and year. Is there a good, easy way to do this?

Answer 1

The easiest way to do this with PHP is

$dateBegin = strtotime("first day of last month");  
$dateEnd = strtotime("last day of last month");

echo date("MYDATEFORMAT", $dateBegin);  
echo "<br>";        
echo date("MYDATEFORMAT", $dateEnd);

Or the last week

if (date('N', time()) == 7) {
$dateBegin = strtotime("-2 weeks Monday");
$dateEnd = strtotime("last Sunday");
} else {
$dateBegin = strtotime("Monday last week"); 
$dateEnd = strtotime("Sunday last week");   
}

Or the last year

$dateBegin = strtotime("1/1 last year");
$dateEnd = strtotime("12/31 this year");

Answer 2

$first = date('Y-m-d', mktime(0, 0, 0, $month, 1, $year));
$last = date('Y-m-t', mktime(0, 0, 0, $month, 1, $year));

See date() in PHP documentation.

Answer 3

From here(get next month last day) that is marked as duplicated, so i can't add comment there, but people can got bad answers from there.

Correct one for last day of next month:

echo ((new DateTime(date('Y-m').'-01'))->modify('+1 month')->format('Y-m-t'));

Correct one for first day of next month:

echo ((new DateTime(date('Y-m').'-01'))->modify('+1 month')->format('Y-m-01'));

Code like this will be providing March from January, so that's not what could be expected.

echo ((new DateTime())->modify('+1 month')->format('Y-m-t'));

Answer 4

Example; I want to get first day and last day of current month.

$month   = (int) date('F');
$year    = (int) date('Y');

date('Y-m-d', mktime(0, 0, 0, $month + 1, 1, $year)); //first
date('Y-m-d', mktime(0, 0, 0, $month + 2, 0, $year)); //last

When you run this for instance at date 2015-01-09, the first and last values will be sequentially;

2015-01-01
2015-01-31

Tested.

Answer 5

By the way @ZombieSheep solution

date ('Y-m-d', mktime(0,0,0,$MM + 1,-1,$YYYY));

does not work it should be

date ('Y-m-d', mktime(0,0,0,$MM + 1,0,$YYYY)); // Day zero instead of -1

Of course @Michał Słaby's accepted solution is the simplest.

Answer 6

The first day of the month is always 1. So it will become

YYYY-MM-01

the last day can be calculated as:

<?php
    $num = cal_days_in_month(CAL_GREGORIAN, 8, 2003); // 31
    echo "There was $num days in August 2003";
?>