How can I check if a string contains only numbers and alphabets ie. is alphanumeric?
Considering you want to check for ASCII Alphanumeric characters, Try this:
"^[a-zA-Z0-9]*$"
. Use this RegEx in String.matches(Regex)
, it will return true if the string is alphanumeric, else it will return false.
public boolean isAlphaNumeric(String s){
String pattern= "^[a-zA-Z0-9]*$";
return s.matches(pattern);
}
If it will help, read this for more details about regex: http://www.vogella.com/articles/JavaRegularExpressions/article.html
See the documentation of Pattern.
Assuming US-ASCII alphabet (a-z, A-Z), you could use \p{Alnum}
.
A regex to check that a line contains only such characters is "^[\\p{Alnum}]*$"
.
That also matches empty string. To exclude empty string: "^[\\p{Alnum}]+$"
.
If you want to include foreign language letters as well, you can try:
String string = "hippopotamus";
if (string.matches("^[\\p{L}0-9']+$")){
string is alphanumeric do something here...
}
Or if you wanted to allow a specific special character, but not any others. For example for # or space, you can try:
String string = "#somehashtag";
if(string.matches("^[\\p{L}0-9'#]+$")){
string is alphanumeric plus #, do something here...
}
try this [0-9a-zA-Z]+ for only alpha and num with one char at-least
..
may need modification so test on it
http://www.regexplanet.com/advanced/java/index.html
Pattern pattern = Pattern.compile("^[0-9a-zA-Z]+$");
Matcher matcher = pattern.matcher(phoneNumber);
if (matcher.matches()) {
}
To check if a String is alphanumeric, you can use a method that goes through every character in the string and checks if it is alphanumeric.
public static boolean isAlphaNumeric(String s){
for(int i = 0; i < s.length(); i++){
char c = s.charAt(i);
if(!Character.isDigit(c) && !Character.isLetter(c))
return false;
}
return true;
}
It's 2016 or later and things have progressed. This matches Unicode alphanumeric strings:
^[\\p{IsAlphabetic}\\p{IsDigit}]+$
See the reference (section "Classes for Unicode scripts, blocks, categories and binary properties"). There's also this answer that I found helpful.