How do we check if a pointer is NULL pointer?

Question

I always think simply if(p != NULL){..} will do the job. But after reading this Stack Overflow question, it seems not.

So what\'s the canonical way to c

Answer 1

The actual representation of a null pointer is irrelevant here. An integer literal with value zero (including 0 and any valid definition of NULL) can be converted to any pointer type, giving a null pointer, whatever the actual representation. So p != NULL, p != 0 and p are all valid tests for a non-null pointer.

You might run into problems with non-zero representations of the null pointer if you wrote something twisted like p != reinterpret_cast<void*>(0), so don't do that.

Although I've just noticed that your question is tagged C as well as C++. My answer refers to C++, and other languages may be different. Which language are you using?

Answer 2

//Do this

int IS_NULL_PTR(char *k){
memset(&k, k, sizeof k);
if(k) { return 71; } ;
return 72;
}
int PRINT_PTR_SAFE(char *KR){
    char *E=KR;;
    if (IS_NULL_PTR(KR)==71){
        printf("%s\r\n",KR);
    } else {
        printf("%s","(null)\r\n");
    }
}
int main(int argc,char *argv[]){
    int i=0;
    char *A=malloc(sizeof(char)*9);
    ;strcpy(A,"hello world");
    for (i=((int)(A))-10;i<1e+40;i++){
        PRINT_PTR_SAFE(i);
    }

}
//Then watch the show!
//Edit as you wish. Just credit me if you really want more of this.