Converting a list of data frames into individual data frames in R [duplicate]

Answer 1

Try list2env(eqRegions,envir=.GlobalEnv)

Answer 2

list2env returns data frames to the global environment whose names are the names in the list. An alternative, if you want to have the same name for the data frames but identified by i from a loop:

for (i in 1:length(eqRegions)) {
  assign(paste0("eqRegions", i), as.data.frame(eqRegions[[i]]))
}

This can be slow if the length if the list gets too long.

Answer 3

attach(eqRegions) should be enough. But I recommend working with them in list form using lapply. I guarantee it will result in simpler code.

Answer 4

As an alternative, a "best practice" when splitting data like this is to keep the data.frames within a list, as provided by split. To process it, you use either one of sapply or lapply (many factors) and capture the output back in a list. For instance:

eqRegionsProcessed <- lapply(eqRegions, function(df) {
    ## do something meaningful here
})

This obviously only works if you are doing the same thing to each data.frame.

If you really must break them out and deal with each data.frame uniquely, then @MatthewPlourde's and @MaratTalipov's answers will work.

Answer 5

This should work. The name of the data.frames created will be equal to the names within eqDataAll$SeismicRegion. Anyways, this practice of populating individual data.frames is not recommended. The more I work with R, the more I love/use list.

lapply(names(eqRegions), function(x) assign(x, eqRegions[[x]], envir = .GlobalEnv))

edit: Use list2env solution posted. Was not aware of list2env function.