subprocess.Popen in different console

Question

I hope this is not a duplicate.

I\'m trying to use subprocess.Popen() to open a script in a separate console. I\'ve tried setting the shell=True

Answer 1

To open in a different console, do (tested on Win7 / Python 3):

from subprocess import Popen, CREATE_NEW_CONSOLE

Popen('cmd', creationflags=CREATE_NEW_CONSOLE)

input('Enter to exit from Python script...')

Related

How can I spawn new shells to run python scripts from a base python script?

Answer 2

On Linux shell=True will do the trick:

command = 'python someFile.py' subprocess.Popen('xterm -hold -e "%s"' % command)

Doesn't work with gnome-terminal as described here:

https://bbs.archlinux.org/viewtopic.php?id=180103

Answer 3

from subprocess import *

c = 'dir' #Windows

handle = Popen(c, stdin=PIPE, stderr=PIPE, stdout=PIPE, shell=True)
print handle.stdout.read()
handle.flush()

If you don't use shell=True you'll have to supply Popen() with a list instead of a command string, example:

c = ['ls', '-l'] #Linux

and then open it without shell.

handle = Popen(c, stdin=PIPE, stderr=PIPE, stdout=PIPE)
print handle.stdout.read()
handle.flush()

This is the most manual and flexible way you can call a subprocess from Python. If you just want the output, go for:

from subproccess import check_output
print check_output('dir')

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To open a new console GUI window and execute X:

import os
os.system("start cmd /K dir") #/K remains the window, /C executes and dies (popup)