jQuery how to find an element based on a data-attribute value?

Question

I\'ve got the following scenario:

var el = \'li\';

and there are 5

\'s on the page each with a data-slide=numb

Answer 1

I improved upon psycho brm's filterByData extension to jQuery.

Where the former extension searched on a key-value pair, with this extension you can additionally search for the presence of a data attribute, irrespective of its value.

(function ($) {

    $.fn.filterByData = function (prop, val) {
        var $self = this;
        if (typeof val === 'undefined') {
            return $self.filter(
                function () { return typeof $(this).data(prop) !== 'undefined'; }
            );
        }
        return $self.filter(
            function () { return $(this).data(prop) == val; }
        );
    };

})(window.jQuery);

Usage:

$('<b>').data('x', 1).filterByData('x', 1).length    // output: 1
$('<b>').data('x', 1).filterByData('x').length       // output: 1

// test data
function extractData() {
  log('data-prop=val ...... ' + $('div').filterByData('prop', 'val').length);
  log('data-prop .......... ' + $('div').filterByData('prop').length);
  log('data-random ........ ' + $('div').filterByData('random').length);
  log('data-test .......... ' + $('div').filterByData('test').length);
  log('data-test=anyval ... ' + $('div').filterByData('test', 'anyval').length);
}

$(document).ready(function() {
  $('#b5').data('test', 'anyval');
});

// the actual extension
(function($) {

  $.fn.filterByData = function(prop, val) {
    var $self = this;
    if (typeof val === 'undefined') {
      return $self.filter(

        function() {
          return typeof $(this).data(prop) !== 'undefined';
        });
    }
    return $self.filter(

      function() {
        return $(this).data(prop) == val;
      });
  };

})(window.jQuery);


//just to quickly log
function log(txt) {
  if (window.console && console.log) {
    console.log(txt);
    //} else {
    //  alert('You need a console to check the results');
  }
  $("#result").append(txt + "<br />");
}

#bPratik {
  font-family: monospace;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>

<div id="bPratik">
  <h2>Setup</h2>
  <div id="b1" data-prop="val">Data added inline :: data-prop="val"</div>
  <div id="b2" data-prop="val">Data added inline :: data-prop="val"</div>
  <div id="b3" data-prop="diffval">Data added inline :: data-prop="diffval"</div>
  <div id="b4" data-test="val">Data added inline :: data-test="val"</div>
  <div id="b5">Data will be added via jQuery</div>
  <h2>Output</h2>
  <div id="result"></div>

  <hr />
  <button onclick="extractData()">Reveal</button>
</div>

Or the fiddle: http://jsfiddle.net/PTqmE/46/

Answer 2

in case you don't want to type all that, here's a shorter way to query by data attribute:

$("ul[data-slide='" + current +"']");

FYI: http://james.padolsey.com/javascript/a-better-data-selector-for-jquery/

Answer 3

When searching with [data-x=...], watch out, it doesn't work with jQuery.data(..) setter:

$('<b data-x="1">'  ).is('[data-x=1]') // this works
> true

$('<b>').data('x', 1).is('[data-x=1]') // this doesn't
> false

$('<b>').attr('data-x', 1).is('[data-x=1]') // this is the workaround
> true

You can use this instead:

$.fn.filterByData = function(prop, val) {
    return this.filter(
        function() { return $(this).data(prop)==val; }
    );
}

$('<b>').data('x', 1).filterByData('x', 1).length
> 1

Answer 4

$("ul").find("li[data-slide='" + current + "']");

I hope this may work better

thanks

Answer 5

I have faced the same issue while fetching elements using jQuery and data-* attribute.

so for your reference the shortest code is here:

This is my HTML Code:

<section data-js="carousel"></section>
<section></section>
<section></section>
<section data-js="carousel"></section>

This is my jQuery selector:

$('section[data-js="carousel"]');
// this will return array of the section elements which has data-js="carousel" attribute.

Answer 6

This selector $("ul [data-slide='" + current +"']"); will work for following structure:

<ul><li data-slide="item"></li></ul>  

While this $("ul[data-slide='" + current +"']"); will work for:

<ul data-slide="item"><li></li></ul>