How to obtain the correct physical size of the monitor?

Question

How can I get the size of the display in centimeters or inches?

This code does not always works correctly:

HDC hdc = CreateDC(_T(\"DISPLAY\"),dd.Devi         


        

Answer 1

Navigating the registry directly is not only unsupported, but actually fails for devices different than yours. (e.g., the one on which I tested your code).

Unlike what some here say, there is an official way of accessing the EDID key path: by use of the Setup API, and specifically SetupDiOpenDevRegKey.

There's some tedious setup involved - Sample code is here.

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EDIT: multiple monitors are handled here.

Answer 2

Windows Vista and upper support new function GetMonitorDisplayAreaSize() http://msdn.microsoft.com/en-us/library/ms775210%28VS.85%29.aspx

Update: It doesn't work properly

Answer 3

You can request LOGPIXELSX from GetDeviceCaps to get the DPI for the display, though it will generally return 96. See also this MSDN article on writing DPI-aware apps.

Answer 4

I found another way. The physical size of the monitor are stored in the EDID, and Windows are almost always copies of its value in the registry. If you can parse EDID, you can read the width and height of the monitor in centimeters.

Update: Added code

BOOL GetMonitorDevice( TCHAR* adapterName, DISPLAY_DEVICE &ddMon )
{
    DWORD devMon = 0;

    while (EnumDisplayDevices(adapterName, devMon, &ddMon, 0))
    {
        if (ddMon.StateFlags & DISPLAY_DEVICE_ACTIVE &&
            ddMon.StateFlags & DISPLAY_DEVICE_ATTACHED) // for ATI, Windows XP
            break;

        devMon++;
    }

    if (ddMon.DeviceString[0] == '\0')
    {
        EnumDisplayDevices(adapterName, 0, &ddMon, 0);
        if (ddMon.DeviceString[0] == '\0')
            _tcscpy_s(ddMon.DeviceString, _T("Default Monitor"));
    }
    return ddMon.DeviceID[0] != '\0';
}

BOOL GetMonitorSizeFromEDID(TCHAR* adapterName, DWORD& Width, DWORD& Height)
{
    DISPLAY_DEVICE ddMon;
    ZeroMemory(&ddMon, sizeof(ddMon));
    ddMon.cb = sizeof(ddMon);

    //read edid
    bool result = false;
    Width = 0;
    Height = 0;
    if (GetMonitorDevice(adapterName, ddMon))
    {
        TCHAR model[8];
        TCHAR* s = _tcschr(ddMon.DeviceID, '\\') + 1;
        size_t len = _tcschr(s, '\\') - s;
        if (len >= _countof(model))
            len = _countof(model) - 1;
        _tcsncpy_s(model, s, len);

        TCHAR *path = _tcschr(ddMon.DeviceID, '\\') + 1;
        TCHAR str[MAX_PATH] = _T("SYSTEM\\CurrentControlSet\\Enum\\DISPLAY\\");
        _tcsncat_s(str, path, _tcschr(path, '\\')-path);
        path = _tcschr(path, '\\') + 1;
        HKEY hKey;
        if(RegOpenKeyEx(HKEY_LOCAL_MACHINE, str, 0, KEY_READ, &hKey) == ERROR_SUCCESS)
        {
            DWORD i = 0;
            DWORD size = MAX_PATH;
            FILETIME ft;
            while(RegEnumKeyEx(hKey, i, str, &size, NULL, NULL, NULL, &ft) == ERROR_SUCCESS)
            {
                HKEY hKey2;
                if(RegOpenKeyEx(hKey, str, 0, KEY_READ, &hKey2) == ERROR_SUCCESS)
                {
                    size = MAX_PATH;
                    if(RegQueryValueEx(hKey2, _T("Driver"), NULL, NULL, (LPBYTE)&str, &size) == ERROR_SUCCESS)
                    {
                        if (_tcscmp(str, path) == 0)
                        {
                            HKEY hKey3;
                            if(RegOpenKeyEx(hKey2, _T("Device Parameters"), 0, KEY_READ, &hKey3) == ERROR_SUCCESS)
                            {
                                BYTE EDID[256];
                                size = 256;
                                if(RegQueryValueEx(hKey3, _T("EDID"), NULL, NULL, (LPBYTE)&EDID, &size) == ERROR_SUCCESS)
                                {
                                    DWORD p = 8;
                                    TCHAR model2[9];

                                    char byte1 = EDID[p];
                                    char byte2 = EDID[p+1];
                                    model2[0]=((byte1 & 0x7C) >> 2) + 64;
                                    model2[1]=((byte1 & 3) << 3) + ((byte2 & 0xE0) >> 5) + 64;
                                    model2[2]=(byte2 & 0x1F) + 64;
                                    _stprintf(model2 + 3, _T("%X%X%X%X"), (EDID[p+3] & 0xf0) >> 4, EDID[p+3] & 0xf, (EDID[p+2] & 0xf0) >> 4, EDID[p+2] & 0x0f);
                                    if (_tcscmp(model, model2) == 0)
                                    {
                                        Width = EDID[22];
                                        Height = EDID[21];
                                        result = true;
                                    }
                                    else
                                    {
                                        // EDID incorrect
                                    }
                                }
                                RegCloseKey(hKey3);
                            }
                        }
                    }
                    RegCloseKey(hKey2);
                }
                i++;
            }
            RegCloseKey(hKey);
        }
    }

    return result;
}

Answer 5

It is not possible to determine the exact physical size of a video device on windows as this depends on quite a lot of variables (e.g. active monitor profile, horizontal/vertical resolution, pixel size, etc.), some of which are not under the control of the computer.

Think for example of projector devices, where the physical size depends on the distance to the projection area which cannot be determined programmatically, as the video projector could be moved manually anytime.

Answer 6

You can't get the real exact size - you can get an approximation that depends on the DPI setting in windows, and the resolution of the screen, but you can't guarantee that this is the real size.

Especially in a multimonitor situation with different displays (say a 19" CRT and 24" LCD). Further, if the display is CRT then the measurement is the tube measurement, and not the display area.

When programs have needed this information exactly in the past, they've shown a gauge onscreen, and had the user hold a piece of paper up to the screen and measure the paper width with the gauge. Given the paper is 8.5" or A4 then you know the width, and you can use the number that they input to figure out the real DPI for a given display. You may need to have them do that for each monitor in a multimonitor setup.

-Adam