Check if string contains word in array

Question

This is for a chat page. I have a $string = \"This dude is a mothertrucker\". I have an array of badwords: $bads = array(\'truck\', \'shot\', etc)

Answer 1

If you want to do with array_intersect(), then use below code :

function checkString(array $arr, $str) {

  $str = preg_replace( array('/[^ \w]+/', '/\s+/'), ' ', strtolower($str) ); // Remove Special Characters and extra spaces -or- convert to LowerCase

  $matchedString = array_intersect( explode(' ', $str), $arr);

  if ( count($matchedString) > 0 ) {
    return true;
  }
  return false;
}

Answer 2

Your best shot should be to run this code on the client side I.e only when JavaScript is available

const fruits = ["Banana", "Orange", "Apple", "Mango"];
const check  = fruits.includes("Mango")
//  console.log(check)

it returned true because mango is in the array. if mango was not in the array it will return false

not PHP, strictly for JavaScript(client side)

Answer 3

1) The simplest way:

if ( in_array( 'eleven',  array('four', 'eleven', 'six') ))
...

2) Another way (while checking arrays towards another arrays):

$keywords=array('one','two','three');
$targets=array('eleven','six','two');
foreach ( $targets as $string ) 
{
  foreach ( $keywords as $keyword ) 
  {
    if ( strpos( $string, $keyword ) !== FALSE )
     { echo "The word appeared !!" }
  }
}

Answer 4

function contains($str, array $arr)
{
    foreach($arr as $a) {
        if (stripos($str,$a) !== false) return true;
    }
    return false;
}

Answer 5

Wanted this?

$string = "This dude is a mothertrucker"; 
$bads = array('truck', 'shot', 'mothertrucker');

    foreach ($bads as $bad) {
        if (strstr($string,$bad) !== false) {
            echo 'NO<br>';
        }
        else {
            echo 'YES<br>';
        }
    }

Answer 6

You can do the filter this way also

$string = "This dude is a mothertrucker";
if (preg_match_all('#\b(truck|shot|etc)\b#', $string )) //add all bad words here.       
    {
  echo "There is a bad word in the string";
    } 
else {
    echo "There is no bad word in the string";
   }