PHP save image file [duplicate]

Answer 1

No need to create a GD resource, as someone else suggested.

$input = 'http://images.websnapr.com/?size=size&key=Y64Q44QLt12u&url=http://google.com';
$output = 'google.com.jpg';
file_put_contents($output, file_get_contents($input));

Note: this solution only works if you're setup to allow fopen access to URLs. If the solution above doesn't work, you'll have to use cURL.

Answer 2

Note: you should use the accepted answer if possible. It's better than mine.

It's quite easy with the GD library.

It's built in usually, you probably have it (use phpinfo() to check)

$image = imagecreatefromjpeg("http://images.websnapr.com/?size=size&key=Y64Q44QLt12u&url=http://google.com");

imagejpeg($image, "folder/file.jpg");

The above answer is better (faster) for most situations, but with GD you can also modify it in some form (cropping for example).

$image = imagecreatefromjpeg("http://images.websnapr.com/?size=size&key=Y64Q44QLt12u&url=http://google.com");
imagecopy($image, $image, 0, 140, 0, 0, imagesx($image), imagesy($image));
imagejpeg($image, "folder/file.jpg");

This only works if allow_url_fopen is true (it is by default)