How can I transform XML into a List or String[]?

Question

How can I transform the following XML into a List or String[]:

  1
  2<         


        

Answer 1

It sounds like you're more after just parsing rather than full XML serialization/deserialization. If you can use LINQ to XML, this is pretty easy:

using System;
using System.Linq;
using System.Xml.Linq;

public class Test
{
    static void Main()
    {
        string xml = "<Ids><id>1</id><id>2</id></Ids>";

        XDocument doc = XDocument.Parse(xml);

        var list = doc.Root.Elements("id")
                           .Select(element => element.Value)
                           .ToList();

        foreach (string value in list)
        {
            Console.WriteLine(value);
        }
    }
}

In fact the call to Elements could omit the argument as there are only id elements, but I thought I'd demonstrate how to specify which elements you want.

Likewise I'd normally not bother calling ToList unless I really needed a List<string> - without it, the result is IEnumerable<string> which is fine if you're just iterating over it once. To create an array instead, use ToArray.

Answer 2

This sample will work with the .NET framework 4.0:

into a List

    List<string> Ids= new List<string>(); 
    Ids= selectedNode.Descendants("Ids").Elements("Id").Select(> x=>x.Value).Where(s =>s!= string.Empty).ToList();

into a string []

    string[] Ids= thisNode
                  .Descendants("Ids")          // Ids element
                  .Elements("Id")              // Id elements
                  .Select(x=>x.Value)          // XElement to string
                  .Where(s =>s!= string.Empty) // must be not empty
                  .ToArray();                  // string to string []

Answer 3

With any type of collection. For example :

<Ids> <id>C:\videotest\file0.txt</id> <id>C:\videotest\file1.txt</id> </Ids>

class FileFormat
    {
        public FileFormat(string path)
        {
            this.path = path;
        }
        public string FullPath
        {
            get { return Path.GetFullPath(path); }
        }
        public string FileName
        {
            get { return Path.GetFileName(path); }
        }
        private string path;
    }

List<FileFormat> Files =
        selectedNode
        .Descendants("Ids")
        .Elements("Id")
        .Select(x => new FileFormat(x.Value))
        .Where(s => s.FileName!=string.Empty)
        .ToList();

Answer 4

the code to convert a string array to xml

items is a string array

items.Aggregate("", (current, x) => current + ("<item>" + x + "</item>"))

Answer 5

You can use Properties class.

Properties prop = new Properties();
prop.loadFromXML(stream);
Set set = prop.keySet();

You can than access Strings from set for each key. Key is element name of xml.

Answer 6

This sample will work with the .NET framework 3.5:

    System.Xml.Linq.XElement element = System.Xml.Linq.XElement.Parse("<Ids>  <id>1</id>  <id>2</id></Ids>");
    System.Collections.Generic.List<string> ids = new System.Collections.Generic.List<string>();
    foreach (System.Xml.Linq.XElement childElement in element.Descendants("id"))
    {
        ids.Add(childElement.Value);
    }