How to count digits, letters, spaces for a string in Python?

Question

I am trying to make a function to detect how many digits, letter, spaces, and others for a string.

Here\'s what I have so far:

def count(x):
    leng         


        

Answer 1

Here's another option:

s = 'some string'

numbers = sum(c.isdigit() for c in s)
letters = sum(c.isalpha() for c in s)
spaces  = sum(c.isspace() for c in s)
others  = len(s) - numbers - letters - spaces

Answer 2

Following code replaces any nun-numeric character with '', allowing you to count number of such characters with function len.

import re
len(re.sub("[^0-9]", "", my_string))

Alphabetical:

import re
len(re.sub("[^a-zA-Z]", "", my_string))

More info - https://docs.python.org/3/library/re.html

Answer 3

def match_string(words):
    nums = 0
    letter = 0
    other = 0
    for i in words :
        if i.isalpha():
            letter+=1
        elif i.isdigit():
            nums+=1
        else:
            other+=1
    return nums,letter,other

x = match_string("Hello World")
print(x)
>>>
(0, 10, 2)
>>>