I have seen questions like this asked many many times but none are helpful
Im trying to submit data to a form on the web ive tried requests, and urllib and none have
import urllib
import urllib2
url = 'http://www.someserver.com/cgi-bin/register.cgi'
values = {'name' : 'Michael Foord',
'location' : 'Northampton',
'language' : 'Python' }
data = urllib.urlencode(values)
req = urllib2.Request(url, data)
response = urllib2.urlopen(req)
the_page = response.read()
This makes a POST request with the data specified in the values. we need urllib to encode the url and then urllib2 to send a request.
If you want to pass q
as a parameter in the URL using requests, use the params
argument, not data
(see Passing Parameters In URLs):
r = requests.get('http://stackoverflow.com', params=data)
This will request https://stackoverflow.com/?q=%5Bpython%5D , which isn't what you are looking for.
You really want to POST
to a form. Try this:
r = requests.post('https://stackoverflow.com/search', data=data)
This is essentially the same as GET
-ting https://stackoverflow.com/questions/tagged/python , but I think you'll get the idea from this.
Mechanize library from python is also great allowing you to even submit forms. You can use the following code to create a browser object and create requests.
import mechanize,re
br = mechanize.Browser()
br.set_handle_robots(False) # ignore robots
br.set_handle_refresh(False) # can sometimes hang without this
br.addheaders = [('User-agent', 'Firefox')]
br.open( "http://google.com" )
br.select_form( 'f' )
br.form[ 'q' ] = 'foo'
br.submit()
resp = None
for link in br.links():
siteMatch = re.compile( 'www.foofighters.com' ).search( link.url )
if siteMatch:
resp = br.follow_link( link )
break
content = resp.get_data()
print content