How to read an http input stream

Question

The code pasted below was taken from java docs on HttpURLConnection.

I get the following error:

readStream(in) 

as there is no suc

Answer 1

a complete code for reading from a webservice in two ways

public void buttonclick(View view) {
    // the name of your webservice where reactance is your method
    new GetMethodDemo().execute("http://wervicename.nl/service.asmx/reactance");
}

public class GetMethodDemo extends AsyncTask<String, Void, String> {
    //see also: 
    // https://developer.android.com/reference/java/net/HttpURLConnection.html
    //writing to see:    https://docs.oracle.com/javase/tutorial/networking/urls/readingWriting.html
    String server_response;
    @Override
    protected String doInBackground(String... strings) {
        URL url;
        HttpURLConnection urlConnection = null;
        try {
            url = new URL(strings[0]);
            urlConnection = (HttpURLConnection) url.openConnection();
            int responseCode = urlConnection.getResponseCode();
            if (responseCode == HttpURLConnection.HTTP_OK) {
                server_response = readStream(urlConnection.getInputStream());
                Log.v("CatalogClient", server_response);
            }
        } catch (MalformedURLException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

        try {
            url = new URL(strings[0]);
            urlConnection = (HttpURLConnection) url.openConnection();
            BufferedReader in = new BufferedReader(new InputStreamReader(
                    urlConnection.getInputStream()));
            String inputLine;
            while ((inputLine = in.readLine()) != null)
                System.out.println(inputLine);
            in.close();
            Log.v("bufferv ", server_response);
        } catch (MalformedURLException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return null;
    }

    @Override
    protected void onPostExecute(String s) {
        super.onPostExecute(s);
        Log.e("Response", "" + server_response);
   //assume there is a field with id editText
        EditText editText = (EditText) findViewById(R.id.editText);
        editText.setText(server_response);
    }
}

Answer 2

Try with this code:

InputStream in = address.openStream();
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
StringBuilder result = new StringBuilder();
String line;
while((line = reader.readLine()) != null) {
    result.append(line);
}
System.out.println(result.toString());

Answer 3

Spring has an util class for that:

import org.springframework.util.FileCopyUtils;

InputStream is = connection.getInputStream();
ByteArrayOutputStream bos = new ByteArrayOutputStream();
FileCopyUtils.copy(is, bos);
String data = new String(bos.toByteArray());

Answer 4

try this code

String data = "";
InputStream iStream = httpEntity.getContent();
BufferedReader br = new BufferedReader(new InputStreamReader(iStream, "utf8"));
StringBuffer sb = new StringBuffer();
String line = "";

while ((line = br.readLine()) != null) {
    sb.append(line);
}

data = sb.toString();
System.out.println(data);

Answer 5

It looks like the documentation is just using readStream() to mean:

Ok, we've shown you how to get the InputStream, now your code goes in readStream()

So you should either write your own readStream() method which does whatever you wanted to do with the data in the first place.