I\'m writing a makefile that compiles a .java
file in a different directory, and then I want to run it, without changing directories. I want to do something alo
I might be misunderstanding the question, but you can compile with
javac /home/MyJavaFile.java
This will create MyJavaFile.class
in /home
You can then run it by including /home
on the classpath. e.g.
java -cp /home MyJavaFile
If you want to generate the class file in a different directory then you can use the -d
option to javac
.
Use the -d
command line parameter with javac
to tell it what directory you'd like to store the compiled class files in. Then, to run the program, simply include this directory in the classpath:
javac -d some/directory myjavafile.java
java -cp some/directory myjavafile
Just to add to the existing answers, you may want the --source-path
flag:
--source-path <path>, -sourcepath <path> Specify where to find input source files
I believe this effectively sets the package root javac
will compile from (i.e. <path>
will be stripped from the expected package name of the files). It's still necessary to enumerate the files to compile, and this should still be relative to the current working directory, not the path passed to --source-path
.
For example, to compile and run from a project's root where source is stored in src/
and you want it build in bin/
:
$ javac --source-path src -d bin src/mypackage/*.java
$ java -cp bin mypackage.Main
This works even from directories elsewhere in the filesystem, e.g.:
$ javac --source-path /some/absolute/path/src -d /some/absolute/path/bin /some/absolute/path/
$ java -cp /some/absolute/path/bin mypackage.Main