Regex: match word that ends with “Id”

Question

I need help putting together a regex that will match word that ends with \"Id\" with case sensitive match.

Answer 1

Try this regular expression:

\w*Id\b

\w* allows word characters in front of Id and the \b ensures that Id is at the end of the word (\b is word boundary assertion).

Answer 2

I would use
\b[A-Za-z]*Id\b
The \b matches the beginning and end of a word i.e. space, tab or newline, or the beginning or end of a string.

The [A-Za-z] will match any letter, and the * means that 0+ get matched. Finally there is the Id.

Note that this will match words that have capital letters in the middle such as 'teStId'.

I use http://www.regular-expressions.info/ for regex reference

Answer 3

This may do the trick:

\b\p{L}*Id\b

Where \p{L} matches any (Unicode) letter and \b matches a word boundary.

Answer 4

How about \A[a-z]*Id\z? [This makes characters before Id optional. Use \A[a-z]+Id\z if there needs to be one or more characters preceding Id.]

Answer 5

Regex ids = new Regex(@"\w*Id\b", RegexOptions.None);

\b means "word break" and \w means any word character. So \w*Id\b means "{stuff}Id". By not including RegexOptions.IgnoreCase, it will be case sensitive.

Answer 6

Gumbo gets my vote, however, the OP doesn't specify whether just "Id" is an allowable word, which means I'd make a minor modification:

\w+Id\b

1 or more word characters followed by "Id" and a breaking space. The [a-zA-Z] variants don't take into account non-English alphabetic characters. I might also use \s instead of \b as a space rather than a breaking space. It would depend if you need to wrap over multiple lines.