Remove char at specific index - python

Question

I have a string that has two \"0\" (str) in it and I want to remove only the \"0\" (str) at index 4

I have tried calling .replace but obviously that removes all \"0\

Answer 1

Another option, using list comprehension and join:

''.join([_str[i] for i in xrange(len(_str)) if i  != 4])

Answer 2

def remove_char(input_string, index):
    first_part = input_string[:index]
    second_part - input_string[index+1:]
    return first_part + second_part

s = 'aababc'
index = 1
remove_char(s,index)
ababc

zero-based indexing

Answer 3

Slicing works (and is the preferred approach), but just an alternative if more operations are needed (but then converting to a list wouldn't hurt anyway):

>>> a = '123456789'
>>> b = bytearray(a)
>>> del b[3]
>>> b
bytearray(b'12356789')
>>> str(b)
'12356789'

Answer 4

Use slicing, rebuilding the string minus the index you want to remove:

newstr = oldstr[:4] + oldstr[5:]

Answer 5

This is my generic solution for any string s and any index i:

def remove_at(i, s):
    return s[:i] + s[i+1:]

Answer 6

as a sidenote, replace doesn't have to move all zeros. If you just want to remove the first specify count to 1:

'asd0asd0'.replace('0','',1)

Out:

'asdasd0'