I have a function e.g.
var test = function () {alert(1);}
How can I get the body of this function?
I assume that the only way is to
If you just want to execute the body of the function (e.g. with eval
or using the Worker
API), you can simply add some code to circumvent all the pitfalls of extracting the body of the function (which, as mentioned by others, is a bad idea in general):
'(' + myFunction + ')()';
I am using this trick in this Worker-related JSFiddle.
I also wrote a more complete library that can:
Check out my CodeBuilder code here.
Note that much of the code takes care of making sure that we get an accurate stacktrace, wherever we execute the serialized function at a later point in time.
This fiddle demonstrates a simplified version of that logic:
JSON.stringify
to properly serialize the function (that comes in handy when, e.g., we want to make it part of a bigger serialization "data package").eval
to un-escape the "JSON-ish"-escaped string (JSON does not allow functions + code, so we must use eval
), and then in another eval
to get back the object we wanted.//# sourceMappingURL
(or the old version //@ sourceMappingURL
) to show the right function name in the stacktrace.Codebuilder
makes use of stacktracejs to fix that.I use the CodeBuilder
stuff in my (now slightly dated) RPC library where you can find some examples of how it is used:
extending @polygenelubricants' answer:
using: .toString()
Testee:
var y = /* olo{lo} */
/* {alala} */function/* {ff} */ x/*{s}ls{
}ls*/(/*{*{*/)/* {ha-ha-ha} */
/*
it's a function
*/
{
return 'x';
// }
}
/*
*/
By indexOf and lastIndexOf:
function getFunctionBody(fn) {
function removeCommentsFromSource(str) {
return str.replace(/(?:\/\*(?:[\s\S]*?)\*\/)|(?:([\s;])+\/\/(?:.*)$)/gm, '$1');
}
var s = removeCommentsFromSource( fn.toString() );
return s.substring(s.indexOf('{')+1, s.lastIndexOf('}'));
};
getFunctionBody(y);
/*
"
return 'x'
"
*/
used: rm comments from js source
This code provides the body when using ES6 arrow functions like var testFn=(q)=>q+1;
function getFunctionBody(test){
var entire = test.toString(); // note: not safe-guarded; this part may fail like this!
return entire.substring((entire.indexOf("{")+1)||(entire.indexOf("=>")+2), entire.lastIndexOf("}")!==-1?entire.lastIndexOf("}"):entire.length);
}
//testing/showcase code
var tests = [
function () {alert(1);},
()=>{return 1;},
q=>q+1
];
for (var i=0;i<tests.length;i++){
console.log(tests[i],getFunctionBody(tests[i]));
}
I originally submitted this code as an edit to polygenelubricants accepted answer, but it was rejected as the changes were considered to be too drastic.
2015 update
Upon revisiting the state of function decompilation, it can said that it's generally safe in certain well-considered use cases and enviroments (e.g: Node.js workers with user defined functions).
It should be put in the same bucket as eval, which is a powerful tool that has its place, but should only be used on rare occasions. Think twice, that's my only advice.
The conclusions from Kangax's new research:
"function decompilation" — a process of getting string representation of a Function object.
Function decompilation is generally recommended against, as it is a non-standard part of the language, and as a result, leads to code being non-interoperable and potentially error-prone.
@kangax on comp.lang.javascript
you can try this functiion:
function extractFunctionBody(fn) {
var reg = /function \((.*)\)[ ]?{(.*)}$/g;
var match = reg.exec(fn.toString().replace(/\n/g, ";"));
if (match){
return match[2];
} else {
return "";
}
}
Try this:
/\{(\s*?.*?)*?\}/g.exec(test.toString())[0]
test.toString() will hold your entire declaration.
/{(\s*?.?)?}/g will match everything between your braces