jQuery check/uncheck radio button onclick

Question

I have this code to check/uncheck a radio button onclick.

I know it is not good for the UI, but I need this.

$(\'#radioinstant\').click(function() {          


        

Answer 1

If you use on click and only check if radio is checked and then deselect, you will never get the radio checked. So maybe easiest is to use classnames like this:

if($(this).hasClass('alreadyChecked')) {//it is already checked
        $('.myRadios').removeClass('alreadyChecked');//remove from all radios
        $(this).prop('checked', false);//deselect this
    }
    else {
        $('.myRadios').removeClass('alreadyChecked');//remove from all
        $(this).addClass('alreadyChecked');//add to only this
    }

Answer 2

I think this is the shortest way. I tested it on Chrome and MS Edge.

$(document).on('click', 'input:radio', function () {
    var check = $(this).attr('checked')
    if (check) $(this).removeAttr('checked').prop('checked',false)
    else $(this).attr('checked', true).prop('checked',true)
})

This piece of code also works on AJAX loaded contents.

Alternatively, You can also use

$(document).on('click mousedown', 'input:radio', function (e) {
    e.preventDefault()
    if ($(this).prop('checked')) $(this).prop('checked', false)
    else $(this).prop('checked', true)
})

This would work better without any exceptions.

Answer 3

I would suggest this:

$('input[type="radio"].toggle').click(function () {
    var $rb = $(this);

    if ($rb.val() === 'on') {
        $rb.val('off');
        this.checked = false;
    }
    else {
        $rb.val('on');
        this.checked = true;
    }
});

Your HTML would look like this:

<input type="radio" class="toggle" value="off" />

Answer 4

toggleAttr() is provided by this very nice and tiny plugin.

Sample code

$('#my_radio').click(function() {
    $(this).toggleAttr('checked');
});

/**
 * toggleAttr Plugin
 */
jQuery.fn.toggleAttr = function(attr) {
    return this.each(function() {
        var $this = $(this);
        $this.attr(attr) ? $this.removeAttr(attr) : $this.attr(attr, attr);
    });
};

Even more fun, demo

You can use place your radio button inside label or button tags and do some nice things.

Answer 5

I took https://stackoverflow.com/a/13575528/80353 and adapted it like this

$(document).ready(function() {

        $('body').on('click', 'input[type="radio"]', function() {
            changeCheckedAttributes($(this));
        });
        function changeCheckedAttributes(elt) {
            $("input[name='"+$(elt).attr("name")+"']:radio").not($(elt)).removeData("chk");
            $("input[name='"+$(elt).attr("name")+"']:radio").not($(elt)).removeAttr("checked");
            $("input[name='"+$(elt).attr("name")+"']:radio").not($(elt)).prop("checked", false);
            $(elt).data("chk",!$(elt).data("chk"));
            $(elt).prop("checked", true);
            $(elt).attr("checked", $(elt).data("chk"));
        }

    });

Answer 6

This last solution is the one that worked for me. I had problem with Undefined and object object or always returning false then always returning true but this solution that works when checking and un-checking.

This code shows fields when clicked and hides fields when un-checked :

$("#new_blah").click(function(){
   if ($(this).attr('checked')) {

            $(this).removeAttr('checked');
    var radioValue = $(this).prop('checked',false);
    // alert("Your are a rb inside 1- " + radioValue);
    // hide the fields is the  radio button is no     
    $("#new_blah1").closest("tr").hide();
    $("#new_blah2").closest("tr").hide();

    } 
    else {

    var radioValue =  $(this).attr('checked', 'checked');
    // alert("Your are a rb inside 2 - " + radioValue);
    // show the fields   when radio button is set to  yes
    $("#new_blah1").closest("tr").show();
    $("#new_blah2").closest("tr").show();

}