In the code below, the AngularJS $http
method calls the URL, and submits the xsrf object as a \"Request Payload\" (as described in the Chrome debugger network t
As of AngularJS v1.4.0, there is a built-in $httpParamSerializer
service that converts any object to a part of a HTTP request according to the rules that are listed on the docs page.
It can be used like this:
$http.post('http://example.com', $httpParamSerializer(formDataObj)).
success(function(data){/* response status 200-299 */}).
error(function(data){/* response status 400-999 */});
Remember that for a correct form post, the Content-Type
header must be changed. To do this globally for all POST requests, this code (taken from Albireo's half-answer) can be used:
$http.defaults.headers.post["Content-Type"] = "application/x-www-form-urlencoded";
To do this only for the current post, the headers
property of the request-object needs to be modified:
var req = {
method: 'POST',
url: 'http://example.com',
headers: {
'Content-Type': 'application/x-www-form-urlencoded'
},
data: $httpParamSerializer(formDataObj)
};
$http(req);
Use AngularJS $http
service and use its post
method or configure $http
function.
The continued confusion surrounding this issue inspired me to write a blog post about it. The solution I propose in this post is better than your current top rated solution because it does not restrict you to parametrizing your data object for $http service calls; i.e. with my solution you can simply continue to pass actual data objects to $http.post(), etc. and still achieve the desired result.
Also, the top rated answer relies on the inclusion of full jQuery in the page for the $.param() function, whereas my solution is jQuery agnostic, pure AngularJS ready.
http://victorblog.com/2012/12/20/make-angularjs-http-service-behave-like-jquery-ajax/
Hope this helps.
As a workaround you can simply make the code receiving the POST respond to application/json data. For PHP I added the code below, allowing me to POST to it in either form-encoded or JSON.
//handles JSON posted arguments and stuffs them into $_POST
//angular's $http makes JSON posts (not normal "form encoded")
$content_type_args = explode(';', $_SERVER['CONTENT_TYPE']); //parse content_type string
if ($content_type_args[0] == 'application/json')
$_POST = json_decode(file_get_contents('php://input'),true);
//now continue to reference $_POST vars as usual
This is what I am doing for my need, Where I need to send the login data to API as form data and the Javascript Object(userData) is getting converted automatically to URL encoded data
var deferred = $q.defer();
$http({
method: 'POST',
url: apiserver + '/authenticate',
headers: { 'Content-Type': 'application/x-www-form-urlencoded' },
transformRequest: function (obj) {
var str = [];
for (var p in obj)
str.push(encodeURIComponent(p) + "=" + encodeURIComponent(obj[p]));
return str.join("&");
},
data: userData
}).success(function (response) {
//logics
deferred.resolve(response);
}).error(function (err, status) {
deferred.reject(err);
});
This how my Userdata is
var userData = {
grant_type: 'password',
username: loginData.userName,
password: loginData.password
}
The following line needs to be added to the $http object that is passed:
headers: {'Content-Type': 'application/x-www-form-urlencoded; charset=UTF-8'}
And the data passed should be converted to a URL-encoded string:
> $.param({fkey: "key"})
'fkey=key'
So you have something like:
$http({
method: 'POST',
url: url,
data: $.param({fkey: "key"}),
headers: {'Content-Type': 'application/x-www-form-urlencoded; charset=UTF-8'}
})
From: https://groups.google.com/forum/#!msg/angular/5nAedJ1LyO0/4Vj_72EZcDsJ
To use new services added with AngularJS V1.4, see