SQLite Order By Date1530019888000

Question

Every record in my SQLite database contains a field which contains a Date stored as a string in the format \'yyyy-MM-dd HH:mm:ss

Answer 1

When you sure the format of text field is yyyy-MM-dd HH:mm:ss (ex.: 2017-01-02 16:02:55), So It works for me simply:

SELECT * FROM Table ORDER BY dateColumn DESC Limit 1

Without any extra date function!

Answer 2

You can convert your column sent_date_time to yyyy-MM-dd format and then order by date:

1) substr(sent_date_time,7,4)||"-"||substr(sent_date_time,1,2)||"-"||substr(sent_date_time,4,2) as date
2) order by date desc

Answer 3

you can do it like this

SELECT * FROM Table ORDER BY date(dateColumn) DESC Limit 1

Answer 4

You can also use the following query

"SELECT * FROM Table ORDER BY strftime('%Y-%m-%d %H:%M:%S'," + dateColumn + ") DESC  Limit 1"

Answer 5

If you do a lot of date sorting/comparison, you may get better results by storing time as ticks rather than strings, here is showing how to get 'now' in ticks with:

((strftime('%s', 'now') - strftime('%S', 'now') + strftime('%f', 'now')) * 1000)

(see https://stackoverflow.com/a/20478329/460084)

Then it's easy to sort, compare, etc ...

Answer 6

For me I had my query this way to solve my problem

select *  from Table order  by datetime(datetimeColumn) DESC LIMIT 1

Since I was storing it as datetime not date column