download file using an ajax request

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旧时难觅i
旧时难觅i 2020-11-21 23:46

I want to send an \"ajax download request\" when I click on a button, so I tried in this way:

javascript:

var xhr = new XMLHttpRequest();
xhr.open(\         


        
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12条回答
  • 2020-11-22 00:24

    To make the browser downloads a file you need to make the request like that:

     function downloadFile(urlToSend) {
         var req = new XMLHttpRequest();
         req.open("GET", urlToSend, true);
         req.responseType = "blob";
         req.onload = function (event) {
             var blob = req.response;
             var fileName = req.getResponseHeader("fileName") //if you have the fileName header available
             var link=document.createElement('a');
             link.href=window.URL.createObjectURL(blob);
             link.download=fileName;
             link.click();
         };
    
         req.send();
     }
    
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  • 2020-11-22 00:32

    It is possible. You can have the download started from inside an ajax function, for example, just after the .csv file is created.

    I have an ajax function that exports a database of contacts to a .csv file, and just after it finishes, it automatically starts the .csv file download. So, after I get the responseText and everything is Ok, I redirect browser like this:

    window.location="download.php?filename=export.csv";
    

    My download.php file looks like this:

    <?php
    
        $file = $_GET['filename'];
    
        header("Cache-Control: public");
        header("Content-Description: File Transfer");
        header("Content-Disposition: attachment; filename=".$file."");
        header("Content-Transfer-Encoding: binary");
        header("Content-Type: binary/octet-stream");
        readfile($file);
    
    ?>
    

    There is no page refresh whatsoever and the file automatically starts downloading.

    NOTE - Tested in the following browsers:

    Chrome v37.0.2062.120 
    Firefox v32.0.1
    Opera v12.17
    Internet Explorer v11
    
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  • 2020-11-22 00:32

    This solution is not very different from those above, but for me it works very well and i think it's clean.

    I suggest to base64 encode the file server side (base64_encode(), if you are using PHP) and send the base64 encoded data to the client

    On the client you do this:

     let blob = this.dataURItoBlob(THE_MIME_TYPE + "," + response.file);
     let uri = URL.createObjectURL(blob);
     let link = document.createElement("a");
     link.download = THE_FILE_NAME,
     link.href = uri;
     document.body.appendChild(link);
     link.click();
     document.body.removeChild(link);
    

    This code puts the encoded data in a link and simulates a click on the link, then it removes it.

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  • 2020-11-22 00:34

    For those looking a more modern approach, you can use the fetch API. The following example shows how to download a spreadsheet file. It is easily done with the following code.

    fetch(url, {
        body: JSON.stringify(data),
        method: 'POST',
        headers: {
            'Content-Type': 'application/json; charset=utf-8'
        },
    })
    .then(response => response.blob())
    .then(response => {
        const blob = new Blob([response], {type: 'application/application/vnd.openxmlformats-officedocument.spreadsheetml.sheet'});
        const downloadUrl = URL.createObjectURL(blob);
        const a = document.createElement("a");
        a.href = downloadUrl;
        a.download = "file.xlsx";
        document.body.appendChild(a);
        a.click();
    })
    

    I believe this approach to be much easier to understand than other XMLHttpRequest solutions. Also, it has a similar syntax to the jQuery approach, without the need to add any additional libraries.

    Of course, I would advise checking to which browser you are developing, since this new approach won't work on IE. You can find the full browser compatibility list on the following link.

    Important: In this example I am sending a JSON request to a server listening on the given url. This url must be set, on my example I am assuming you know this part. Also, consider the headers needed for your request to work. Since I am sending a JSON, I must add the Content-Type header and set it to application/json; charset=utf-8, as to let the server know the type of request it will receive.

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  • 2020-11-22 00:35

    there is another solution to download a web page in ajax. But I am referring to a page that must first be processed and then downloaded.

    First you need to separate the page processing from the results download.

    1) Only the page calculations are made in the ajax call.

    $.post("CalculusPage.php", { calculusFunction: true, ID: 29, data1: "a", data2: "b" },
    
           function(data, status) 
           {
                if (status == "success") 
                {
                    /* 2) In the answer the page that uses the previous calculations is downloaded. For example, this can be a page that prints the results of a table calculated in the ajax call. */
                    window.location.href = DownloadPage.php+"?ID="+29;
                }               
           }
    );
    
    // For example: in the CalculusPage.php
    
        if ( !empty($_POST["calculusFunction"]) ) 
        {
            $ID = $_POST["ID"];
    
            $query = "INSERT INTO ExamplePage (data1, data2) VALUES ('".$_POST["data1"]."', '".$_POST["data2"]."') WHERE id = ".$ID;
            ...
        }
    
    // For example: in the DownloadPage.php
    
        $ID = $_GET["ID"];
    
        $sede = "SELECT * FROM ExamplePage WHERE id = ".$ID;
        ...
    
        $filename="Export_Data.xls";
        header("Content-Type: application/vnd.ms-excel");
        header("Content-Disposition: inline; filename=$filename");
    
        ...
    

    I hope this solution can be useful for many, as it was for me.

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  • 2020-11-22 00:36

    @Joao Marcos solution works for me but I had to modify the code to make it work on IE, below if what the code looks like

           downloadFile(url,filename) {
            var that = this;
            const extension =  url.split('/').pop().split('?')[0].split('.').pop();
    
            var req = new XMLHttpRequest();
            req.open("GET", url, true);
            req.responseType = "blob";
            req.onload = function (event) {
                const fileName = `${filename}.${extension}`;
                const blob = req.response;
    
                if (window.navigator.msSaveBlob) { // IE
                    window.navigator.msSaveOrOpenBlob(blob, fileName);
                } 
                const link = document.createElement('a');
                link.href = window.URL.createObjectURL(blob);                
                link.download = fileName;
                link.click();
                URL.revokeObjectURL(link.href);
    
            };
    
            req.send();
        },
    
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