SQL Order By Count

Question

If I have a table and data like this:

ID |  Name  |  Group   

1    Apple     A    

2    Boy       A

3    Cat       B

4    Dog       C

5    Elep      C

         


        

Answer 1

Below gives me opposite of what you have. (Notice Group column)

SELECT
    *
FROM
    myTable
GROUP BY
    Group_value,
    ID
ORDER BY
    count(Group_value)

Let me know if this is fine with you...

I am trying to get what you want too...

Answer 2

...none of the other answers seem to do what the asker asked.

For table named 'things' with column 'group':

SELECT
  things.*, counter.count
FROM
  things
LEFT JOIN (
  SELECT
    things.group, count(things.group) as count
  FROM
    things
  GROUP BY
    things.group
) counter ON counter.group = things.group
ORDER BY
  counter.count ASC;

which gives:

id | name  | group | count 
---------------------------
3  | Cat   | B     | 1
1  | Apple | A     | 2
2  | Boy   | A     | 2
4  | Dog   | C     | 3
5  | Elep  | C     | 3
6  | Fish  | C     | 3

Answer 3

Try :

SELECT count(*),group FROM table GROUP BY group ORDER BY group

to order by count descending do

SELECT count(*),group FROM table GROUP BY group ORDER BY count(*) DESC

This will group the results by the group column returning the group and the count and will return the order in group order

Answer 4

SELECT * FROM table 
group by `Group`
ORDER BY COUNT(Group)

Answer 5

SELECT group, COUNT(*) FROM table GROUP BY group ORDER BY group

or to order by the count

SELECT group, COUNT(*) AS count FROM table GROUP BY group ORDER BY count DESC

Answer 6

Try using below Query:

SELECT
    GROUP,
    COUNT(*) AS Total_Count
FROM
    TABLE
GROUP BY
    GROUP
ORDER BY
    Total_Count DESC