Why does changing an Array in JavaScript affect copies of the array?

后端 未结 11 1833
礼貌的吻别
礼貌的吻别 2020-11-22 00:16

I\'ve written the following JavaScript:

var myArray = [\'a\', \'b\', \'c\'];
var copyOfMyArray = myArray;
copyOfMyArray.splice(0, 1);
alert(myArray); // aler         


        
相关标签:
11条回答
  • 2020-11-22 00:29

    Well, the only possible answer — and the correct one — is that you're not actually copying the array. When you write

    var copyOfArray = array;
    

    you're assigning a reference to the same array into another variable. They're both pointing at the same object, in other words.

    0 讨论(0)
  • 2020-11-22 00:31

    You don't have any copies.
    You have multiple variables holding the same array.

    Similarly, you have multiple variables holding the same number.

    When you write copyOfMyNumber = ..., you're putting a new number into the variable.
    That's like writing copyOfMyArray = ....

    When you write copyOfMyArray.splice, you're modifying the original array.
    That isn't possible with numbers because numbers are immutable and cannot be modified,

    0 讨论(0)
  • 2020-11-22 00:34

    So everyone here has done a great job of explaining why this is happening - I just wanted to drop a line and let you know how I was able to fix this - pretty easily:

    thingArray = ['first_thing', 'second_thing', 'third_thing']
    function removeFirstThingAndPreserveArray(){
      var copyOfThingArray = [...thingArray]
      copyOfThingArray.shift();
      return copyOfThingArray;
    }
    

    This is using the ... spread syntax.

    Spread Syntax Source

    EDIT: As to the why of this, and to answer your question:

    What is the difference between an array and a number in JavaScript that it seems changing an array changes the value of a copy of the array, where as changing a number does not change the value of a copy of the number?

    The answer is that in JavaScript, arrays and objects are mutable, while strings and numbers and other primitives are immutable. When we do an assignment like:

    var myArray = ['a', 'b', 'c']; var copyOfMyArray = myArray;

    copyOfMyArray is really just a reference to myArray, not an actual copy.

    I would recommend this article, What are immutable and mutable data structures?, to dig deeper into the subject.

    MDN Glossary: Mutable

    0 讨论(0)
  • 2020-11-22 00:35

    An array, or an object in javascript always holds the same reference unless you clone or copy. Here is an exmaple:

    http://plnkr.co/edit/Bqvsiddke27w9nLwYhcl?p=preview

    // for showing that objects in javascript shares the same reference
    
    var obj = {
      "name": "a"
    }
    
    var arr = [];
    
    //we push the same object
    arr.push(obj);
    arr.push(obj);
    
    //if we change the value for one object
    arr[0].name = "b";
    
    //the other object also changes
    alert(arr[1].name);
    

    For object clone, we can use .clone() in jquery and angular.copy(), these functions will create new object with other reference. If you know more functions to do that, please tell me, thanks!

    0 讨论(0)
  • 2020-11-22 00:38

    An array in JavaScript is also an object and variables only hold a reference to an object, not the object itself. Thus both variables have a reference to the same object.

    Your comparison with the number example is not correct btw. You assign a new value to copyOfMyNumber. If you assign a new value to copyOfMyArray it will not change myArray either.

    You can create a copy of an array using slice [docs]:

    var copyOfMyArray = myArray.slice(0);
    

    But note that this only returns a shallow copy, i.e. objects inside the array will not be cloned.

    0 讨论(0)
提交回复
热议问题