I have an XML document with a default namespace indicated at the root. Something like this:
You need to declare the namespace in your XSLT, and use it in XPath expressions. E.g.:
<xsl:stylesheet ... xmlns:my="http://www.mysite.com">
<xsl:template match="/my:MyRoot"> ... </xsl:template>
</xsl:stylesheet>
Note that you must provide some prefix if you want to refer to elements from that namespace in XPath. While you can just do xmlns="..."
without the prefix, and it will work for literal result elements, it won't work for XPath - in XPath, an unprefixed name is always considered to be in namespace with blank URI, regardless of any xmlns="..."
in scope.
If you use XSLT 2.0, specify xpath-default-namespace="http://www.example.com"
in the stylesheet
section.
If this was kind of name space problem, there is room to try to modify two things in the xslt file:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:my="http://www.w3.org/2001/XMLSchema">
<xsl:template match="/" >
<soap:Envelope xsl:version="1.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
<soap:Body>
<NewRoot xmlns="http://wherever.com">
<NewChild>
<ChildID>ABCD</ChildID>
<ChildData>
<xsl:value-of select="/my:MyRoot/my:MyChild1/my:MyData"/>
</ChildData>
</NewChild>
</NewRoot>
</soap:Body>
</soap:Envelope>
</xsl:template>
</xsl:stylesheet>