Converting a sentence string to a string array of words in Java

Question

I need my Java program to take a string like:

\"This is a sample sentence.\"

and turn it into a string array like:

{\"this\         


        

Answer 1

Here is a solution in plain and simple C++ code with no fancy function, use DMA to allocate a dynamic string array, and put data in array till you find a open space. please refer code below with comments. I hope it helps.

#include<bits/stdc++.h>
using namespace std;

int main()
{

string data="hello there how are you"; // a_size=5, char count =23
//getline(cin,data); 
int count=0; // initialize a count to count total number of spaces in string.
int len=data.length();
for (int i = 0; i < (int)data.length(); ++i)
{
    if(data[i]==' ')
    {
        ++count;
    }
}
//declare a string array +1 greater than the size 
// num of space in string.
string* str = new string[count+1];

int i, start=0;
for (int index=0; index<count+1; ++index) // index array to increment index of string array and feed data.
{   string temp="";
    for ( i = start; i <len; ++i)
    {   
        if(data[i]!=' ') //increment temp stored word till you find a space.
        {
            temp=temp+data[i];
        }else{
            start=i+1; // increment i counter to next to the space
            break;
        }
    }str[index]=temp;
}


//print data 
for (int i = 0; i < count+1; ++i)
{
    cout<<str[i]<<" ";
}

    return 0;
}

Answer 2

You can use BreakIterator.getWordInstance to find all words in a string.

public static List<String> getWords(String text) {
    List<String> words = new ArrayList<String>();
    BreakIterator breakIterator = BreakIterator.getWordInstance();
    breakIterator.setText(text);
    int lastIndex = breakIterator.first();
    while (BreakIterator.DONE != lastIndex) {
        int firstIndex = lastIndex;
        lastIndex = breakIterator.next();
        if (lastIndex != BreakIterator.DONE && Character.isLetterOrDigit(text.charAt(firstIndex))) {
            words.add(text.substring(firstIndex, lastIndex));
        }
    }

    return words;
}

Test:

public static void main(String[] args) {
    System.out.println(getWords("A PT CR M0RT BOUSG SABN NTE TR/GB/(G) = RAND(MIN(XXX, YY + ABC))"));
}

Ouput:

[A, PT, CR, M0RT, BOUSG, SABN, NTE, TR, GB, G, RAND, MIN, XXX, YY, ABC]

Answer 3

You can just split your string like that using this regular expression

String l = "sofia, malgré tout aimait : la laitue et le choux !" <br/>
l.split("[[ ]*|[,]*|[\\.]*|[:]*|[/]*|[!]*|[?]*|[+]*]+");

Answer 4

Use string.replace(".", "").replace(",", "").replace("?", "").replace("!","").split(' ') to split your code into an array with no periods, commas, question marks, or exclamation marks. You can add/remove as many replace calls as you want.

Answer 5

The easiest and best answer I can think of is to use the following method defined on the java string -

String[] split(String regex)

And just do "This is a sample sentence".split(" "). Because it takes a regex, you can do more complicated splits as well, which can include removing unwanted punctuation and other such characters.

Answer 6

I already did post this answer somewhere, i will do it here again. This version doesn't use any major inbuilt method. You got the char array, convert it into a String. Hope it helps!

import java.util.Scanner;

public class SentenceToWord 
{
    public static int getNumberOfWords(String sentence)
    {
        int counter=0;
        for(int i=0;i<sentence.length();i++)
        {
            if(sentence.charAt(i)==' ')
            counter++;
        }
        return counter+1;
    }

    public static char[] getSubString(String sentence,int start,int end) //method to give substring, replacement of String.substring() 
    {
        int counter=0;
        char charArrayToReturn[]=new char[end-start];
        for(int i=start;i<end;i++)
        {
            charArrayToReturn[counter++]=sentence.charAt(i);
        }
        return charArrayToReturn;
    }

    public static char[][] getWordsFromString(String sentence)
    {
        int wordsCounter=0;
        int spaceIndex=0;
        int length=sentence.length();
        char wordsArray[][]=new char[getNumberOfWords(sentence)][]; 
        for(int i=0;i<length;i++)
        {
            if(sentence.charAt(i)==' ' || i+1==length)
            {
            wordsArray[wordsCounter++]=getSubString(sentence, spaceIndex,i+1); //get each word as substring
            spaceIndex=i+1; //increment space index
            }
        }
        return  wordsArray; //return the 2 dimensional char array
    }


    public static void main(String[] args) 
    {
    System.out.println("Please enter the String");
    Scanner input=new Scanner(System.in);
    String userInput=input.nextLine().trim();
    int numOfWords=getNumberOfWords(userInput);
    char words[][]=new char[numOfWords+1][];
    words=getWordsFromString(userInput);
    System.out.println("Total number of words found in the String is "+(numOfWords));
    for(int i=0;i<numOfWords;i++)
    {
        System.out.println(" ");
        for(int j=0;j<words[i].length;j++)
        {
        System.out.print(words[i][j]);//print out each char one by one
        }
    }
    }

}