SQL query to check if a name begins and ends with a vowel

Question

I want to query the list of CITY names from the table STATION(id, city, longitude, latitude) which have vowels as both their first and last charact

Answer 1

My simple solution :::

SELECT DISTINCT CITY

FROM STATION

WHERE CITY LIKE '[a,e,i,o,u]%[a,e,i,o,u]';

Answer 2

You can use LEFT() and RIGHT() functions. Left(CITY,1) will get the first character of CITY from left. Right(CITY,1) will get the first character of CITY from right (last character of CITY).

DISTINCT is used to remove duplicates. To make the comparison case-insensitive, we will use the LOWER() function.

SELECT DISTINCT CITY
FROM STATION
WHERE LOWER(LEFT(CITY,1)) IN ('a', 'e', 'i', 'o', 'u') AND
      LOWER(RIGHT(CITY,1)) IN ('a', 'e', 'i', 'o', 'u')

Answer 3

Try this for beginning with vowel

Oracle:

select distinct *field* from *tablename* where SUBSTR(*sort field*,1,1) IN('A','E','I','O','U') Order by *Sort Field*;

Answer 4

Select distinct(city) from station where city RLIKE '^[aeiouAEIOU]'

Very simple answer.

Answer 5

You could use a regular expression:

SELECT DISTINCT city
FROM   station
WHERE  city RLIKE '^[aeiouAEIOU].*[aeiouAEIOU]$'

Answer 6

For MS access or MYSQL server

SELECT city FROM station
WHERE City LIKE '[aeiou]%'and City LIKE '%[aeiou]';