How do I replace NA values with zeros in an R dataframe?

Question

I have a data frame and some columns have NA values.

How do I replace these NA values with zeroes?

Answer 1

Another dplyr pipe compatible option with tidyrmethod replace_na that works for several columns:

require(dplyr)
require(tidyr)

m <- matrix(sample(c(NA, 1:10), 100, replace = TRUE), 10)
d <- as.data.frame(m)

myList <- setNames(lapply(vector("list", ncol(d)), function(x) x <- 0), names(d))

df <- d %>% replace_na(myList)

You can easily restrict to e.g. numeric columns:

d$str <- c("string", NA)

myList <- myList[sapply(d, is.numeric)]

df <- d %>% replace_na(myList)

Answer 2

You can use replace()

For example:

> x <- c(-1,0,1,0,NA,0,1,1)
> x1 <- replace(x,5,1)
> x1
[1] -1  0  1  0  1  0  1  1

> x1 <- replace(x,5,mean(x,na.rm=T))
> x1
[1] -1.00  0.00  1.00  0.00  0.29  0.00 1.00  1.00

Answer 3

dplyr example:

library(dplyr)

df1 <- df1 %>%
    mutate(myCol1 = if_else(is.na(myCol1), 0, myCol1))

Note: This works per selected column, if we need to do this for all column, see @reidjax's answer using mutate_each.

Answer 4

For a single vector:

x <- c(1,2,NA,4,5)
x[is.na(x)] <- 0

For a data.frame, make a function out of the above, then apply it to the columns.

Please provide a reproducible example next time as detailed here:

How to make a great R reproducible example?

Answer 5

It is also possible to use tidyr::replace_na.

    library(tidyr)
    df <- df %>% mutate_all(funs(replace_na(.,0)))

Answer 6

if you want to assign a new name after changing the NAs in a specific column in this case column V3, use you can do also like this

my.data.frame$the.new.column.name <- ifelse(is.na(my.data.frame$V3),0,1)