Swift performSelector:withObject:afterDelay: is unavailable [duplicate]

Answer 1

You could do this:

var timer = NSTimer.scheduledTimerWithTimeInterval(0.1, target: self, selector: Selector("someSelector"), userInfo: nil, repeats: false)

func someSelector() {
    // Something after a delay
}

SWIFT 3

let timer = Timer.scheduledTimer(timeInterval: 0.1, target: self, selector: #selector(someSelector), userInfo: nil, repeats: false)

func someSelector() {
    // Something after a delay
}

Answer 2

Swift is statically typed so the performSelector: methods are to fall by the wayside.

Instead, use GCD to dispatch a suitable block to the relevant queue — in this case it'll presumably be the main queue since it looks like you're doing UIKit work.

EDIT: the relevant performSelector: is also notably missing from the Swift version of the NSRunLoop documentation ("1 Objective-C symbol hidden") so you can't jump straight in with that. With that and its absence from the Swiftified NSObject I'd argue it's pretty clear what Apple is thinking here.

Answer 3

Swift 4

DispatchQueue.main.asyncAfter(deadline: .now() + 0.1) {
    // your function here
}

Swift 3

DispatchQueue.main.asyncAfter(deadline: .now() + .seconds(0.1)) {
    // your function here
}

Swift 2

let dispatchTime: dispatch_time_t = dispatch_time(DISPATCH_TIME_NOW, Int64(0.1 * Double(NSEC_PER_SEC))) 
dispatch_after(dispatchTime, dispatch_get_main_queue(), { 
    // your function here 
})