PDO Prepared Inserts multiple rows in single query

Question

I am currently using this type of SQL on MySQL to insert multiple rows of values in one single query:

INSERT INTO `tbl` (`key1`,`key2`) VALUES (\'r1v1\',\'r1         


        

Answer 1

This worked for me

$sql = 'INSERT INTO table(pk_pk1,pk_pk2,date,pk_3) VALUES '; 
$qPart = array_fill(0, count($array), "(?, ?,UTC_TIMESTAMP(),?)");
$sql .= implode(",", $qPart);
$stmt =    DB::prepare('base', $sql);
$i = 1;
foreach ($array as $value) { 
  $stmt->bindValue($i++, $value);
  $stmt->bindValue($i++, $pk_pk1);
  $stmt->bindValue($i++, $pk_pk2); 
  $stmt->bindValue($i++, $pk_pk3); 
} 
$stmt->execute();

Answer 2

The Accepted Answer by Herbert Balagtas works well when the $data array is small. With larger $data arrays the array_merge function becomes prohibitively slow. My test file to create the $data array has 28 cols and is about 80,000 lines. The final script took 41s to complete.

Using array_push() to create $insert_values instead of array_merge() resulted in a 100X speed up with execution time of 0.41s.

The problematic array_merge():

$insert_values = array();

foreach($data as $d){
 $question_marks[] = '('  . placeholders('?', sizeof($d)) . ')';
 $insert_values = array_merge($insert_values, array_values($d));
}

To eliminate the need for array_merge(), you can build the following two arrays instead:

//Note that these fields are empty, but the field count should match the fields in $datafields.
$data[] = array('','','','',... n ); 

//getting rid of array_merge()
array_push($insert_values, $value1, $value2, $value3 ... n ); 

These arrays can then be used as follows:

function placeholders($text, $count=0, $separator=","){
    $result = array();
    if($count > 0){
        for($x=0; $x<$count; $x++){
            $result[] = $text;
        }
    }

    return implode($separator, $result);
}

$pdo->beginTransaction();

foreach($data as $d){
 $question_marks[] = '('  . placeholders('?', sizeof($d)) . ')';
}

$sql = "INSERT INTO table (" . implode(",", array_keys($datafield) ) . ") VALUES " . implode(',', $question_marks);

$stmt = $pdo->prepare ($sql);
try {
    $stmt->execute($insert_values);
} catch (PDOException $e){
    echo $e->getMessage();
}
$pdo->commit();

Answer 3

Here is my simple approach.

    $values = array();
    foreach($workouts_id as $value){
      $_value = "(".$value.",".$plan_id.")";
      array_push($values,$_value);
    }
    $values_ = implode(",",$values);

    $sql = "INSERT INTO plan_days(id,name) VALUES" . $values_."";
    $stmt = $this->conn->prepare($sql);
    $stmt->execute();

Answer 4

Two possible approaches:

$stmt = $pdo->prepare('INSERT INTO foo VALUES(:v1_1, :v1_2, :v1_3),
    (:v2_1, :v2_2, :v2_3),
    (:v2_1, :v2_2, :v2_3)');
$stmt->bindValue(':v1_1', $data[0][0]);
$stmt->bindValue(':v1_2', $data[0][1]);
$stmt->bindValue(':v1_3', $data[0][2]);
// etc...
$stmt->execute();

Or:

$stmt = $pdo->prepare('INSERT INTO foo VALUES(:a, :b, :c)');
foreach($data as $item)
{
    $stmt->bindValue(':a', $item[0]);
    $stmt->bindValue(':b', $item[1]);
    $stmt->bindValue(':c', $item[2]);
    $stmt->execute();
}

If the data for all the rows are in a single array, I would use the second solution.