PHP sprintf escaping %

Question

I want the following output:-

About to deduct 50% of € 27.59 from your Top-Up account.

when I do something like this:-

Answer 1

Escape it with another %:

$stringWithVariables = 'About to deduct 50%% of %s %s from your Top-Up account.';

Answer 2

What about this:

$variablesArray[0] = '%';
$variablesArray[1] = '€';
$variablesArray[2] = 27.59;
$stringWithVariables = 'About to deduct 50%s of %s %s from your Top-Up account.';
echo vsprintf($stringWithVariables, $variablesArray);

Just add your percent sign in your variables array

Answer 3

It is very easy.

Put another % in front of the original % to escape it.

For example,

$num=23;
printf("%%d of 23 = %d",$num);

Output:

%d of 23 = 23