Zipping streams using JDK8 with lambda (java.util.stream.Streams.zip)

Question

In JDK 8 with lambda b93 there was a class java.util.stream.Streams.zip in b93 which could be used to zip streams (this is illustrated in the tutorial Exploring Java8 Lambda

Answer 1

I humbly suggest this implementation. The resulting stream is truncated to the shorter of the two input streams.

public static <L, R, T> Stream<T> zip(Stream<L> leftStream, Stream<R> rightStream, BiFunction<L, R, T> combiner) {
    Spliterator<L> lefts = leftStream.spliterator();
    Spliterator<R> rights = rightStream.spliterator();
    return StreamSupport.stream(new AbstractSpliterator<T>(Long.min(lefts.estimateSize(), rights.estimateSize()), lefts.characteristics() & rights.characteristics()) {
        @Override
        public boolean tryAdvance(Consumer<? super T> action) {
            return lefts.tryAdvance(left->rights.tryAdvance(right->action.accept(combiner.apply(left, right))));
        }
    }, leftStream.isParallel() || rightStream.isParallel());
}

Answer 2

Using the latest Guava library (for the Streams class) you should be able to do

final Map<String, String> result = 
    Streams.zip(
        collection1.stream(), 
        collection2.stream(), 
        AbstractMap.SimpleEntry::new)
    .collect(Collectors.toMap(e -> e.getKey(), e  -> e.getValue()));