How to call a function after delay in Kotlin?

Question

As the title, is there any way to call a function after delay (1 second for example) in Kotlin?

Answer 1

There is also an option to use Handler -> postDelayed

 Handler().postDelayed({
                    //doSomethingHere()
                }, 1000)

Answer 2

Many Ways

1. Using Handler class

Handler().postDelayed({
    TODO("Do something")
    }, 2000)

2. Using Timer class

Timer().schedule(object : TimerTask() {
    override fun run() {
        TODO("Do something")
    }
}, 2000)

Shorter

Timer().schedule(timerTask {
    TODO("Do something")
}, 2000)

Shortest

Timer().schedule(2000) {
    TODO("Do something")
}

3. Using Executors class

Executors.newSingleThreadScheduledExecutor().schedule({
    TODO("Do something")
}, 2, TimeUnit.SECONDS)

Answer 3

A simple example to show a toast after 3 seconds :

fun onBtnClick() {
    val handler = Handler()
    handler.postDelayed({ showToast() }, 3000)
}

fun showToast(){
    Toast.makeText(context, "Its toast!", Toast.LENGTH_SHORT).show()
}

Answer 4

You can use Schedule

inline fun Timer.schedule(
    delay: Long, 
    crossinline action: TimerTask.() -> Unit
): TimerTask (source)

example (thanks @Nguyen Minh Binh - found it here: http://jamie.mccrindle.org/2013/02/exploring-kotlin-standard-library-part-3.html)

import java.util.Timer
import kotlin.concurrent.schedule

Timer("SettingUp", false).schedule(500) { 
   doSomething()
}

Answer 5

val timer = Timer()
timer.schedule(timerTask { nextScreen() }, 3000)