EDIT : Summary of answers
In the following, B is a subclass of A.
It\'s a matter of terminology; ctors and dtors are not in
Technically, destructors ARE inherited. But in normal circumstances, the inherited destructors are not directly used for a derived class; they're invoked because the derived class's own destructor calls them in order to destroy its own "base class subobjects" as a step within destroying the larger object. And in the unusual circumstances where you do directly use a base class destructor on a derived object, it's very difficult to avoid Undefined Behavior.
This example comes straight from the C++ Standard (12.4p12).
struct B {
virtual ~B() { }
};
struct D : B {
~D() { }
};
D D_object;
typedef B B_alias;
B* B_ptr = &D_object;
void f() {
D_object.B::~B(); // calls B's destructor
B_ptr->~B(); // calls D's destructor
B_ptr->~B_alias(); // calls D's destructor
B_ptr->B_alias::~B(); // calls B's destructor
B_ptr->B_alias::~B_alias(); // calls B's destructor
}
If ~B
were not an inherited member of D
, the first statement in f
would be ill-formed. As it is, it's legal C++, though extremely dangerous.