BASH copy all files except one

Question

I would like to copy all files out of a dir except for one named Default.png. It seems that there are a number of ways to do this. What seems the most effective to you?

Answer 1

I'd just do:

cp srcdir/* destdir/ ; rm destdir/Default.png

unless the files are big. Otherwise use e.g.

find srcdir -type f/ |grep -v Default.png$ |xargs -ILIST cp LIST destdir/

Answer 2

# chattr +i /files_to_exclude
# cp source destination
# chattr -i /files_to_exclude

Answer 3

This works great for copying everything except node modules. enjoy and thanks to the answers above I have just added on to it. Rsync is better in my opinion than CP as you can see progress bar without asking for it.

   rsync -av fromDirectory/ ToDirectory/ --exclude=node_modules

Answer 4

Should be as follows:

cp -r !(Default.png) /dest

If copying to a folder nested in the current folder (called example in the case below) you need to omit that directory also:

cp -r !(Default.png|example) /example

Answer 5

Simple, if src/ only contains files:

find src/ ! -name Default.png -exec cp -t dest/ {} +

If src/ has sub-directories, this omits them, but does copy files inside of them:

find src/ -type f ! -name Default.png -exec cp -t dest/ {} +

If src/ has sub-directories, this does not recurse into them:

find src/ -type f -maxdepth 1 ! -name Default.png -exec cp -t dest/ {} +

Answer 6

use the shell's expansion parameter with regex

cp /<path>/[^not_to_copy_file]* .

Everything will be copied except for the not_to_copy_file

-- if something is wrong with this. please Specify !