How can I extract all values from a dictionary in Python?

Question

I have a dictionary d = {1:-0.3246, 2:-0.9185, 3:-3985, ...}.

How do I extract all of the values of d into a list l?

Answer 1

dictionary_name={key1:value1,key2:value2,key3:value3}
dictionary_name.values()

Answer 2

Call the values() method on the dict.

Answer 3

To see the keys:

for key in d.keys():
    print(key)

To get the values that each key is referencing:

for key in d.keys():
    print(d[key])

Add to a list:

for key in d.keys():
    mylist.append(d[key])

Answer 4

Use values()

>>> d = {1:-0.3246, 2:-0.9185, 3:-3985}

>>> d.values()
<<< [-0.3246, -0.9185, -3985]

Answer 5

For nested dicts, lists of dicts, and dicts of listed dicts, ... you can use

def get_all_values(d):
    if isinstance(d, dict):
        for v in d.values():
            yield from get_all_values(v)
    elif isinstance(d, list):
        for v in d:
            yield from get_all_values(v)
    else:
        yield d 

An example:

d = {'a': 1, 'b': {'c': 2, 'd': [3, 4]}, 'e': [{'f': 5}, {'g': 6}]}

list(get_all_values(d)) # returns [1, 2, 3, 4, 5, 6]

PS: I love yield. ;-)

Answer 6

For Python 3, you need:

list_of_dict_values = list(dict_name.values())