Given two Date()
objects, where one is less than the other, how do I loop every day between the dates?
for(loopDate = startDate; loopDate < e
Here's a way to do it by making use of the way adding one day causes the date to roll over to the next month if necessary, and without messing around with milliseconds. Daylight savings aren't an issue either.
var now = new Date();
var daysOfYear = [];
for (var d = new Date(2012, 0, 1); d <= now; d.setDate(d.getDate() + 1)) {
daysOfYear.push(new Date(d));
}
Note that if you want to store the date, you'll need to make a new one (as above with new Date(d)
), or else you'll end up with every stored date being the final value of d
in the loop.
If you want an efficient way with milliseconds:
var daysOfYear = [];
for (var d = begin; d <= end; d = d + 86400000) {
daysOfYear.push(new Date(d));
}
Based on Jayarjo's answer:
var loopDate = new Date();
loopDate.setTime(datFrom.valueOf());
while (loopDate.valueOf() < datTo.valueOf() + 86400000) {
alert(loopDay);
loopDate.setTime(loopDate.valueOf() + 86400000);
}
I think I found an even simpler answer, if you allow yourself to use Moment.js:
// cycle through last five days, today included
// you could also cycle through any dates you want, mostly for
// making this snippet not time aware
const currentMoment = moment().subtract(4, 'days');
const endMoment = moment().add(1, 'days');
while (currentMoment.isBefore(endMoment, 'day')) {
console.log(`Loop at ${currentMoment.format('YYYY-MM-DD')}`);
currentMoment.add(1, 'days');
}
<script src="https://cdn.jsdelivr.net/npm/moment@2/moment.min.js"></script>